Answer:sofa
Explanation:the weight of the mass of that object can be heavy (er) than the rest
Answer:
yes, it is a magnet.
Explanation:
The electrons that are travelling through the wire go in 1 direction allowing it to create a magnetic field around its area.
Answer: 2.5 seconds
Explanation:
We know that the acceleration is:
a(t) = 1.7 m/s^2
To get the velocity function, we must integrate over time, and we will get:
v(t) = (1.7m/s^2)*t + v0
Where v0 is the initial velocity, in this case, we assume that we start at 23.6m/s, then the initial velocity is:
v0 = 23.6 m/s
Then the velocity equation is:
v(t) = (1.7m/s^2)*t + 23.6 m/s
Now we want to find the value of t such v(t) = 27.8 m/s
Then:
v(t) = 27.8 m/s = (1.7m/s^2)*t + 23.6 m/s
27.8 m/s - 23.6 m/s = (1.7m/s^2)*t
4.2 m/s = (1.7m/s^2)*t
4.2m/s/(1.7m/s^2) = t = 2.5 s
Then at that acceleration, you need 2.5 seconds.
Answer:
Zero Kelvin
Explanation:
The average kinetic energy of the particles in a gas is related to the absolute temperature of the gas by (for an ideal monoatomic gas):

where
k is the Boltzmann constant
T is the absolute temperature
The average kinetic energy is the energy possessed by the particles due to their motion; we see that this energy becomes zero when T = 0, which means when the substance reaches a temperature of zero Kelvin. Therefore, this means that at this temperature all the particles stop moving.
Dimensional analysis is a method of checking the dimensions of each value in an equation. I will give you an example.

Is a know equation which equates energy and mass. So our question is, is this true or not? The method is following:
knowing that c has the dimension of [m/s] and m has [kg], what is the dimension of E? So here the dimensional analysis begins.
![E = mc^2 \Rightarrow [E] = \text{kg} \cdot \left( \frac{\text{m}} {\text{s}}\right)^2 = \text{kgms}^{-2}](https://tex.z-dn.net/?f=E%20%3D%20mc%5E2%20%5CRightarrow%20%5BE%5D%20%3D%20%5Ctext%7Bkg%7D%20%5Ccdot%20%5Cleft%28%20%5Cfrac%7B%5Ctext%7Bm%7D%7D%20%7B%5Ctext%7Bs%7D%7D%5Cright%29%5E2%20%3D%20%5Ctext%7Bkgms%7D%5E%7B-2%7D)
This can be used also to solve "equations" to prove certain dimensions of unknown constants.