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maksim [4K]
3 years ago
5

Find f((1)/(3)) if f(n)=3n

Mathematics
2 answers:
olga nikolaevna [1]3 years ago
8 0

Answer:

  • 1

Step-by-step explanation:

Given

  • f(n) = 3n

To find

  • f(1/3) =?

Substitute n with 1/3 and calculate

  • f(1/3) = 3*1/3 = 1
Viktor [21]3 years ago
7 0

Answer: The answer is 1 sweetie

Step-by-step explanation: Given

f(n) = 3n

To find

f(1/3) =?

Substitute n with 1/3 and calculate

f(1/3) = 3*1/3 = 1

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Write a linear equation in standard form that satisfies the given set of conditions. X-intercept: 3, y-intercept: 5
Artyom0805 [142]

The linear equation in standard form is y=\frac{-5}{3}x +5.

<h3>Linear Function</h3>

An equation can be represented by a linear function. The standard form for the linear equation is: ax+b , for example, y=7x+2. Where:

a= the slope. It can be calculated for  \frac{\Delta x }{\Delta y}.

b= the constant term that represents the y-intercept.

The question gives: X-intercept:3  and  y-intercept: 5. Then,

  • The x-intercept is the point that y=0, then the x-intercept point is (3,0).
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With this information, you can find the slope (a).

a=\frac{\Delta y }{\Delta x}= \frac{0-5}{3-0} =\frac{-5}{3}

The question gives the coefficient b since it gives the y-intercept=5.

Therefore the linear equation is : y=\frac{-5}{3}x +5.

Read more about the linear equations here:

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4 0
2 years ago
The table shows the relationship between a, the area of a rectangle, and h, its height, when the base remains constant.
olganol [36]

Answer:

a = 4h.

Step-by-step explanation:

Area (a) = base (b) * height (h).

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I have no idea how to do this, it is due in two days. Hopefully someone sees this before then.
elena-14-01-66 [18.8K]

Hello,

m\ \widehat{ABC}=x\\m\ \widehat{BAC}=2*x\\\\So:\\ x+2x=90^o\\x=30^o\\

cos(30^o)=\dfrac{\sqrt{3} }{2} \\

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cos(30^o)=\frac{BC}{BA} \\\\BA=\dfrac{cos(30^o)}{BC} \\\\BA=\frac{\dfrac{\sqrt{3} }{2} }{24} =16*\sqrt{3} \\\\

sin(30^o)=\dfrac{1 }{2} =\dfrac{AC}{AB} \\\\AC=\dfrac{1}{2} *16\sqrt{3} =8\sqrt{3}

In the triangle ACB,

cos(30^o)=\dfrac{AC}{AL} \\\\AL=\dfrac{8\sqrt{3} *2}{\sqrt{3} } =16\\

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