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LiRa [457]
3 years ago
8

What is the distance between -45 and -98 on a number line?

Mathematics
1 answer:
bearhunter [10]3 years ago
3 0
B) 53 l -98 l - l -45 l
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What is the slope of a line that is perpendicular to the line whose equation is 2y = 3x - 1? -3 - -
Shalnov [3]

Answer: 2/3x

Step-by-step explanation:

First, you need to simplify your original line to point slope formula. Dividing the whole thing by 2 to get y by itself leaves you with

y = 3/2x - 1/2

Any perpendicular line has the opposite slope to the line it is perpendicular to, so you flip the slope to get 2/3x

8 0
3 years ago
According to one cosmological theory, there were equal amounts of the two uranium isotopes 235U and 238U at the creation of the
FromTheMoon [43]

Answer:

6 billion years.

Step-by-step explanation:

According to the decay law, the amount of the radioactive substance that decays is proportional to each instant to the amount of substance present. Let P(t) be the amount of ^{235}U and Q(t) be the amount of ^{238}U after t years.

Then, we obtain two differential equations

                               \frac{dP}{dt} = -k_1P \quad \frac{dQ}{dt} = -k_2Q

where k_1 and k_2 are proportionality constants and the minus signs denotes decay.

Rearranging terms in the equations gives

                             \frac{dP}{P} = -k_1dt \quad \frac{dQ}{Q} = -k_2dt

Now, the variables are separated, P and Q appear only on the left, and t appears only on the right, so that we can integrate both sides.

                         \int \frac{dP}{P} = -k_1 \int dt \quad \int \frac{dQ}{Q} = -k_2\int dt

which yields

                      \ln |P| = -k_1t + c_1 \quad \ln |Q| = -k_2t + c_2,

where c_1 and c_2 are constants of integration.

By taking exponents, we obtain

                     e^{\ln |P|} = e^{-k_1t + c_1}  \quad e^{\ln |Q|} = e^{-k_12t + c_2}

Hence,

                            P  = C_1e^{-k_1t} \quad Q  = C_2e^{-k_2t},

where C_1 := \pm e^{c_1} and C_2 := \pm e^{c_2}.

Since the amounts of the uranium isotopes were the same initially, we obtain the initial condition

                                 P(0) = Q(0) = C

Substituting 0 for P in the general solution gives

                         C = P(0) = C_1 e^0 \implies C= C_1

Similarly, we obtain C = C_2 and

                                P  = Ce^{-k_1t} \quad Q  = Ce^{-k_2t}

The relation between the decay constant k and the half-life is given by

                                            \tau = \frac{\ln 2}{k}

We can use this fact to determine the numeric values of the decay constants k_1 and k_2. Thus,

                     4.51 \times 10^9 = \frac{\ln 2}{k_1} \implies k_1 = \frac{\ln 2}{4.51 \times 10^9}

and

                     7.10 \times 10^8 = \frac{\ln 2}{k_2} \implies k_2 = \frac{\ln 2}{7.10 \times 10^8}

Therefore,

                              P  = Ce^{-\frac{\ln 2}{4.51 \times 10^9}t} \quad Q  = Ce^{-k_2 = \frac{\ln 2}{7.10 \times 10^8}t}

We have that

                                          \frac{P(t)}{Q(t)} = 137.7

Hence,

                                   \frac{Ce^{-\frac{\ln 2}{4.51 \times 10^9}t} }{Ce^{-k_2 = \frac{\ln 2}{7.10 \times 10^8}t}} = 137.7

Solving for t yields t \approx 6 \times 10^9, which means that the age of the  universe is about 6 billion years.

5 0
3 years ago
Simplify (3х2 – 2) + (2х2 – бх + 3).
kolbaska11 [484]

Answer:

5x^2 -6x +1

Step-by-step explanation:

(3х^2 – 2) + (2х^2 – бх + 3).

Combine like terms

(3х^2  + 2х^2 – бх + 3-2)

5x^2 -6x +1

4 0
3 years ago
the lengths of the sides of a triangle are consecutive odd integers.if the perimeter of the triangle is 27 what is are the lengt
Umnica [9.8K]
The lengths of each side are 9
5 0
3 years ago
Read 2 more answers
How to tell if an ordered pair is a solution to a function
Evgen [1.6K]
A) yes
B) yes
C) no

For each of these, substitute the value of x in the ordered pair into x in the function.

For A, x = -5; -5<2, so the piece of the function we want is f(x) = 3.  In our ordered pair, y=f(x)=3, so yes, it is a solution.

For B, x = 2; 2≤2<6, so the piece of the function we want is f(x) = -x+1.  In our ordered pair, y=f(x)=-1; -2+1=-1, so yes, it is a solution.

For C, x = 8; 8≥6, so the piece of the function we want is f(x) = x.  In our ordered pair, y=f(x)=-7; -7≠8, so no, it is not a solution.
5 0
3 years ago
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