To find the zeros of this equation you need to first set it equal to zero
2x2 + 16x - 9 = 0
But since you can't FOIL this equation you need to move the non-variable number over
2x2 +16x = 9
Now solve for x by pulling an x out of the equation
x(2x + 16) = 9
x = 9
2x +16 = 9
2x = -7
x = -7/2
So your zeros would be at x = 9, and -7/2
The final solution is all the values that make <span><span><span><span><span>(<span>x+4</span>)</span><span>(<span>x<span>−4</span></span>)</span></span><span>(<span><span>x2</span>+4</span>)</span></span>=0</span><span><span><span><span>x+4</span><span>x<span>-4</span></span></span><span><span>x2</span>+4</span></span>=0</span></span> true.<span>x=<span>−4</span>,4,<span>2i</span>,<span><span>−2</span><span>i</span></span></span>
No, it’s not correct. The y-axis on the graph represents the profits p(x) so the minimum number of units produced should be when the a horizontal line at y = 590 first intersects the parabola drawn left to right, and not a vertical line at x = 590 because that represents the profit as 590 units are produced.
Answer:
x = 10
Step-by-step explanation: 10/2 = 5 + 1 = 6
The highest is 3 does this help u?
