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icang [17]
3 years ago
15

Mark took a loan out for $25,690 to purchase a truck. At an interest rate of 5.2% compounded annually, how much total will he ha

ve paid after 5 years? *
Mathematics
2 answers:
kogti [31]3 years ago
8 0

Answer: he would have paid $33101 after 5 years

Step-by-step explanation:

We would apply the formula for determining compound interest which is expressed as

A = P(1+r/n)^nt

Where

A = total amount paid at the end of t years

r represents the interest rate.

n represents the periodic interval at which it was compounded.

P represents the principal or initial amount taken as loan.

From the information given,

P = 25690

r = 5.2% = 5.2/100 = 0.052

n = 1 because it was compounded once in a year.

t = 5 years

Therefore,.

A = 25690(1+0.052/1)^1 × 5

A = 25690(1.052)^5

A = 33101

Inga [223]3 years ago
3 0

Answer:

I think the answer is 1335.88

Step-by-step explanation:

5.2% of 25,690 is 1335.88

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total number of pen (n)= 15

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number of pen choosing on monday = 3

total number of pen choosing on tuesday=3

note that the total number of pen is constant (15) since he returned the pen back .

probability of picking a pen that has never been used on tuesday = 9/15 = 3/5

probability of not picking a pen that has never been used on tuesday = 1-3/5=2/5

probability of picking a pen that has been used on tuesday = 6/15 = 2/5

probability of not picking a pen that has not been used on tuesday= 1- 2/5= 3/5

on tuesday, 3 balls were chosen at random and we need to calculate the probability that none of them has never been used .

we know that

probability of ball that none of the 3 pen has never being used on tuesday = 1 - probability that 3 of the pens has been used on tuesday.

to calculate the probability that 3 of the pen has been used on tuesday, we use the binomial probability distribution

p(x=r) = nCr * p^{r} * q^{n-r}

n= total number of pens=15

r = number of pen chosen on tuesday = 3

p = probability of picking a pen that has never been used on tuesday = 9/15 = 3/5

q = probability of not picking a pen that has never been used on tuesday = 1-3/5=2/5

by slotting in the parameters, we have that

p(x=3) = 15C3 * (\frac{2}{5})^{3} * (\frac{3}{5})^{12}

p(x=3) = 455 * 0.4^{3} * 0.6^{12}

p(x=3) = 455 * 0.064 * 0.002176

p(x=3) = 0.0633

thus probability that 3 of the pens has been used on tuesday. = 0.0633

probability of ball that none of the 3 pen has never being used on tuesday  = 1 - 0.0633 = 0.9337

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3 years ago
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