Answer:
See explanation
Step-by-step explanation:
Consider triangles PTS and QTR. In these triangles,
- given;
- given;
- as vertical angles when lines PR and SQ intersect.
Thus,
by AAS postulate.
Congruent triangles have congruent corresponding sides, so

Consider segments PR and QS:
![PR=PT+TR\ [\text{Segment addition postulate}]\\ \\QS=QT+TS\ [\text{Segment addition postulate}]\\ \\PT=QT\ [\text{Proven}]\\ \\ST=RT\ [\text{Given}]](https://tex.z-dn.net/?f=PR%3DPT%2BTR%5C%20%5B%5Ctext%7BSegment%20addition%20postulate%7D%5D%5C%5C%20%5C%5CQS%3DQT%2BTS%5C%20%5B%5Ctext%7BSegment%20addition%20postulate%7D%5D%5C%5C%20%5C%5CPT%3DQT%5C%20%5B%5Ctext%7BProven%7D%5D%5C%5C%20%5C%5CST%3DRT%5C%20%5B%5Ctext%7BGiven%7D%5D)
So,
![PR=SQ\ [\text{Substitution property}]](https://tex.z-dn.net/?f=PR%3DSQ%5C%20%5B%5Ctext%7BSubstitution%20property%7D%5D)
Let's see which of these best measures the data.
The mean is the average, or the sum of all numbers divided by the total numbers there are.
4.8 + 3 + 2.7 + 4.4 + 4.8 + 9.9 = 29.6
There are 6 numbers total.
29.6/6 = 4.93.
The mean is 4.93.
Let's try our median. The median is the middle number of a sequence listed from least to greatest. I will make the list for you.
2.7, 3, 4.4, 4.8, 4.8, 9.9.
Cross out the smallest number with the greatest number.
3, 4.4, 4.8, 4.8.
4.4, 4.8.
Since we do not have a middle number, we must see what number is in the middle of 4.4, and 4.8. To determine this, we must average. Add 4.4 and 4.8, then divide by 2.
9.2/2 = 4.6.
4.6 is our median.
The mode is the number that appears the most, so let's find the number that is the most frequent.
4.8 is our mode.
The best number that will fit in this to make it work out is 4.6.
The median is your answer, B.)
I hope this helps!
Sum of interior angles = 180
180 - 60 = 120
120/4 = 30
m<L = m<A = 60
m<M = 30
m<C = m<N = 3(m<M) = 3(30) = 90
Answer:
Yeah
Step-by-step explanation:
-2 is the answer
----------------------------
You're Welcome.