9514 1404 393
Answer:
(B) 4
Step-by-step explanation:
Consider the units column. The only sum of 3 and a single digit that will end in 1 is the sum ...
3 + 8 = 11
This tells you A = 8, so the top number is 1983, and the middle number is B78.
Considering the first two columns, we know that 83 +78 = 161, so there must be a carry of 1 into the third column. That makes it have the sum ...
1 + 9 + B = <something ending in 4>
We know the something cannot be 04 or 24, so must be 14. Then ...
10 + B = 14 ⇒ B = 4
__
So, the whole sum is ...
1983 +478 = 2461
and the letter values are ...
Here is how to work the problems and write the expressions.
It causes very low gravity but it still has a bit of gravity. Hope it helped! ;-) <3
Step one: set the base of each term to be the same (10)
(10ˣ)(10²)²ˣ = (10³)⁵
(10ˣ) (10⁴ˣ)= (10¹⁵)
10⁵ˣ = 10¹⁵
Because the indices are the same we can equate the two.
5x = 15
x = 3
Check 10⁵ˣ³ = 10¹⁵ 10¹⁵=10¹⁵
The answer is realistic. I hope this helps ! :)
