Y = -15 is the answer and blah
The volume of a square pyramid is (1/3)(area of base)(height of pyramid).
Here the area of the base is (10 ft)^2 = 100 ft^2.
13 ft is the height of one of the triangular sides, but not the height of the pyramid. To find the latter, draw another triangle whose upper vertex is connected to the middle of one of the four equal sides of the base by a diagonal of length 13 ft. That "middle" is 5 units straight down from the upper vertex. Thus, you have a triangle with known hypotenuse (13 ft) and known opposite side 5 feet (half of 10 ft). What is the height of the pyramid?
To find this, use the Pyth. Thm.: (5 ft)^2 + y^2 = (13 ft)^2. y = 12 ft.
Then the vol. of the pyramid is (1/3)(area of base)(height of pyramid) =
(1/3)(100 ft^2)(12 ft) = 400 ft^3 (answer)
Answer:
11x
Step-by-step explanation:
They have the same variable so just add the two numbers
Use trigonometric ratios.
Use angle(19)
Adjacent side of angle measure 19 is X
The hypotenuse is 21.
Use the cosine
Cos(19)=x/21
Plug in calculator
(21)cos(19)=19.85
Round to the nearest tenth. Which means the 8 rounds up to 9.
Answer: 19.9
