Question

Write the equation in standard form of a circle with center (-7,2), tangent to the y-axis.

Answer 1

Answer:

$(x+7)^{2}+ (y-2)^{2}=49$

Step-by-step explanation:

It is given that circle is a tangent to y axis, which tells us that the distance between the centre point and y axis is the radius of the triangle.

Formula for equation of circle with centre (x1,y1) and radius r is

$(x-x1)^{2}+ (y-y1)^{2}=r^{2}$

In the given case distance between the centre and y axis is 7 units so radius would be 7 and the centre point is (-7,2),

the equation of circle is ,

$(x+7)^{2}+ (y-2)^{2}=7^{2}$

$(x+7)^{2}+ (y-2)^{2}=49$

Hence the abow equation is the circle equation.