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Artemon [7]
3 years ago
8

How many different simple random sampmes of size 5 can be obtained from a pppulation whose size is 43?​

Mathematics
1 answer:
Nesterboy [21]3 years ago
4 0

Answer:

Number of random samples = 962598

Step-by-step explanation:

A random sample represents  the responses for a certain survey of a part of the population.

A sample size is the part of the population being surveyed.

For a population N the number of different random samples that can be chosen for a sample size x can be calculated as = NCx

This can be calculated as :

NCx=\frac{N!}{x!(N-x)!}

Given:

Population size = 43

Sample size = 5

Number of random samples = 43C5

⇒ \frac{43!}{5!(43-5)!}

⇒ \frac{43!}{5!(38)!}

⇒ \frac{43\times42\times41\times40\times39}{5\times4\times3\times2\times1}    [Canceling out the common terms]

⇒  962598   (Answer)

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Answer:

0.3667

0.2727

Step-by-step explanation:

a)

P (Blue) = P (large and Blue) + P (mid and Blue) + P (small and Blue)

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sergij07 [2.7K]

Answer:

a) sample size is 40

Step-by-step explanation:

(a)

\sigma=4 minutes

Margin of error, E is 75 seconds E=75/60= 1.25 minutes.

The level of significance \alpha= 0.05 for 95% level of significance

For 95% confidence interval z_{\frac{\alpha}{2}}=1.96 from standard deviation table

Sample size required, n

n=\left (\frac{z_{\frac{\alpha}{2}}\cdot \sigma}{E} \right )^{2}=\left (\frac{1.96\cdot4}{75/60} \right )^{2}=39.337984

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Keywords:

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Answer: n = -25

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