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3 years ago

How many different simple random sampmes of size 5 can be obtained from a pppulation whose size is 43?

Mathematics

1 answer:

Nesterboy [21]3 years ago

4 0

Answer:

Number of random samples = 962598

Step-by-step explanation:

A random sample represents the responses for a certain survey of a part of the population.

A sample size is the part of the population being surveyed.

For a population $N$ the number of different random samples that can be chosen for a sample size $x$ can be calculated as = $NCx$

This can be calculated as :

$NCx=\frac{N!}{x!(N-x)!}$

Given:

Population size = 43

Sample size = 5

Number of random samples = $43C5$

⇒ $\frac{43!}{5!(43-5)!}$

⇒ $\frac{43!}{5!(38)!}$

⇒ $\frac{43\times42\times41\times40\times39}{5\times4\times3\times2\times1}$ [Canceling out the common terms]

⇒ $962598$ (Answer)

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Step-by-step explanation:

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3 years ago

Mr and mrs smith buy tickets for themselves and their four children. the cost of an adult ticket is ? 6 more than the adult tick

kirill115 [55]

Answer:

child's ticket = 4.75 adult ticket=10.75.

Step-by-step explanation:

The cost of an adult ticket is 6 more than that of a child ticket, so will be denoted by c+6. Now, we are told that the cost of four child tickets and two adult tickets is 40.50, so we can put this in an equation and solve for c:

(c+6)+(c+6)+c+c+c+c=40.50

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3 years ago

John's current salary is 40000 per year.His annual pay raise is always a percent of his salary.What would his salary be if he re

ad-work [718]

Answer:

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Step-by-step explanation:

According to question,

salary of MR. John = $ 40000 per year

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So, X = 40000 (1 + $\frac{4}{100}$ )^4

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3 years ago

Jillian buys 200 shares of a company at $150 a share. She sells them at $175 a share. What is her capital gain or capital loss?

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3 years ago

Read 2 more answers

The owner of the Rancho Grande has 3,060 yd of fencing with which to enclose a rectangular piece of grazing land situated along

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Answer:

1170450 yd^2

Step-by-step explanation:

The first thing is to calculate the necessary perimeter, which would be like this:

2 * a + b = 3060

if we solve for b, we are left with:

b = 3060-2 * a

Now for the area it would be:

A = a * b = a * (3060-2 * a )

A = 3060 * a -2 * a ^ 2

To maximize the area, we calculate the derivative with respect to "a":

dA / da = d [3060 * a -2 * a ^ 2

]/gives

dA / day = 3060 - 4 * a

If we equal 0:

0 = 3060 - 4 * a

4 * a = 3060

a = 3060/4

a = 765 and d

Therefore b:

b = 3060 - 2 * a = 3060 - 1530 = 1530

A = a * b

A = 765 * 1530

A = 1170450 and d ^ 2

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3 years ago

How many different simple random sampmes of size 5 can be obtained from a pppulation whose size is 43?​

How many different simple random sampmes of size 5 can be obtained from a pppulation whose size is 43?