You can just simplify to make an equivalent equation:
(2)(3x + 8) = 5 ⇒ 6x + 16 = 5
Answer:

Hope it helped,
BioTeacher101
<em>(If you have any questions feel free to ask them in the comments)</em>
Step-by-step explanation:
Amount of acid = 14.9% of 331 mL solution
= 0.149×(331 mL)
= 49.3 mL acid
Answer:
12 boys
Step-by-step explanation:
From the above question:
Number of boys = 3
Number of girls = 2
Boys: Girls
3:2
Let :
a = boys
b = girls
Hence, a : b = 3 : 2
a/b = 3/2
Cross Multiply
2a = 3b .......... Equation 1
a = 3b/2
If four more girls join the class, there will be the same number of boys and girls
Hence,
a: b + 4 = 3 : 3
a/b + 4 = 3/3
Cross Multiply
3a = 3(b + 4)
3a = 3b + 12 ........ Equation (2)
From Equation 1: a = 3b/2
Substitute 3b/2 for a in Equation 2 we have:
3a = 3b + 12 .........Equation 2
3(3b/2) = 3b + 12
9b/2 = 3b + 12
Cross Multiply
9b = 2(3b + 12)
9b= 6b + 24
9b - 6b = 24
3b = 24
b = 8
Substitute 8 for b in Equation 1
a = 3b/2
a = 3 × 8/2
a = 24/2
a = 12
Therefore, the number of boys in the class is 12
Step-by-step explanation:
(2a+3b)(4a²-6ab+9b²
(2a+3b){(2a)²-2a×3b+(3b)²}
Because (a³+b³)=(a+b)(a²-ab+b²)
Therefore,
(2a+3b){(2a)²-2a×3b+(3b)²}
=(2a)³+(3b)³
By substituting the values , we get
- (2a)³+(3b)³
- (2×3)³+(3×(-5))³
- 6³+(-15)³
- 216+(-3375)
- 216-3375
- -3159
Answer:
<u>Russell runs 9/50 of a mile or 0.18 miles in one minute.</u>
Step-by-step explanation:
1. Let's review the data given to us for solving the question:
Distance run by Russell = 9/10 of a mile
Time Russell runs 9/10 of a mile = 5 minutes
2. How many miles does he run in one minute?
Speed of Russell = Distance run by Russell / Time Russell runs
Speed of Russell = (9/10) / 5
Speed of Russell = 9/10 * 1/5 = 9/50
Russell runs 9/50 of a mile in one minute. If we want to express the answer in decimals, we have : 9/50 = 0.18
<u>Russell runs 9/50 of a mile or 0.18 miles in one minute</u>