<span>We never really used the acronym "IMA", or ideal mechanical advantage, but I'm assuming you are trying to increase the leverage and ease the effort. If so, the answer is false. You want larger movement on the effort side, and smaller movement on the resistant side of the fulcrum.</span>
Answer:
The time taken for the train to cross the bridge is 9.01 s
Explanation:
Given;
length of the train, L₁ = 90 m
length of the bridge, L₂ = 0.06 m
speed of the train, v = 10 m/s
Total distance to be traveled, = L₁ + L₂
= 90 m + 0.06 m
= 90.06 m
Time of motion = Distance / speed
Time of motion = 90.06 / 10
Time of motion = 9.006 s ≅ 9.01 s
Therefore, the time taken for the train to cross the bridge is 9.01 s
WHTATATATTSSHSJSD ....... 22
Explanation:
by the formula, v²-u²=2aS
S=12m, a=2m/s², v=25m/s, u=?
v²-u²=2aS
25²-u²=2×2×12
-u²=48-625
-u²=-577
u²=577
u=√577
u = 24.02m/s
hope this helps you.
