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3 years ago

The IMA of a lever can be increased by decreasing the length between the applied effort and the pivot.

Physics

2 answers:

AVprozaik [17]3 years ago

4 0

Explanation:

The ideal mechanical advantage of a lever is defined as the ratio of applied resistance force to the applied effort force. It can be also defined as the ratio of effort arm to the load arm. It is given by :

$IMA=\dfrac{d_1}{d_2}$

$d_1$ = effort arm

$d_2$ = load arm

If the length between the applied effort and the pivot is decreased, the IMA of a lever will decreased. This is due to the direct relation between IMA and effort arm. So, the given statement is false.

mina [271]3 years ago

3 0

<span>We never really used the acronym "IMA", or ideal mechanical advantage, but I'm assuming you are trying to increase the leverage and ease the effort. If so, the answer is false. You want larger movement on the effort side, and smaller movement on the resistant side of the fulcrum.</span>

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Answer:

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Explanation:

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3 years ago

A river flows due south with a speed of 2.0 m/s .You steer a motorboat across the river; your velocity relative to the water is

mihalych1998 [28]

Answer:

a) $v_m =\sqrt{v^2_x + v^2_y} = \sqrt{(2m/s)^2 +(4.8 m/s)^2}= 5.2 m/s$

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c) $t= \frac{w}{v_m}= \frac{600m}{4.8 m/s}= 125 s$

d) $Y = 2 m/s * 125 s = 250m$

So it would be 250 to the South

Explanation:

Part a

For this case the figure attached shows the illustration for the problem.

We know that $v_y = 2 m/s$ represent the velocity of the river to the south.

We have the velocity of the motorboard relative to the water and on this case is $V_x= 4.8 m/s$

And we want to find the velocity of the motord board relative to the Earth $v_m$

And we can find this velocity from the Pythagorean Theorem.

$v_m =\sqrt{v^2_x + v^2_y} = \sqrt{(2m/s)^2 +(4.8 m/s)^2}= 5.2 m/s$

Part b

We can find the direction with the following formula:

$\theta= tan^{-1} \frac{v_y}{v_x} = tan^{-1} (\frac{2}{4.8})= 22.62$ degrees and on this case to the South of the East.

Part c

For this case we can use the following definition

$D = Vt$

The distance would be D = w = 600 m and the velocity V = 4.8m/s and if we solve for t we got:

$t= \frac{w}{v_m}= \frac{600m}{4.8 m/s}= 125 s$

Part d

For this case we can use the same definition but now using the y compnent we have:

$Y = v_y t$

And replacing we got:

$Y = 2 m/s * 125 s = 250m$

So it would be 250 to the South

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Answer:

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