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grigory [225]
3 years ago
11

Ethan drove a 1500 kg car around a circular track with a radius of 75 m. If the magnitude of the centripetal acceleration is 2 m

/s2, what is the car's speed?
A)2.25 m/s
B)20 m/s
C)37.5 m/s
D)150 m/s ​
Physics
1 answer:
Aloiza [94]3 years ago
5 0

Answer:

12.25 m/s

Explanation:

The following data were obtained from the question:

Mass (m) = 1500 Kg

Radius (r) = 75 m

Centripetal acceleration (a) = 2 m/s²

Velocity (v) =?

Centripetal acceleration (a) is related to the velocity (v) and radius (r) according to the following formula:

a = v²/r

Thus, we can obtained the velocity of the car by using the above formula as illustrated below:

Radius (r) = 75 m

Centripetal acceleration (a) = 2 m/s²

Velocity (v) =?

a = v²/r

2 = v²/75

Cross multiply

v² = 2 × 75

v² = 150

Take the square root of both side.

v = √150

v = 12.25 m/s

Thus, the speed of the car is 12.25 m/s.

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erica [24]

Answer:

0.737 m/s²

Explanation:

Given:

v₀ = 0 m/s

v = 8.20 m/s

Δx = 45.6 m

Find: a

v² = v₀² + 2aΔx

(8.20 m/s)² = (0 m/s)² + 2a (45.6 m)

a = 0.737 m/s²

8 0
3 years ago
Cecil writes the equation for the reaction of hydrogen and oxygen below.
Mademuasel [1]

Answer:

2h20

Explanation:

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4 years ago
a. A beam of light is incident from air on the surface of a liquid. If the angle of incidence is 26.7° and the angle of refracti
Diano4ka-milaya [45]

Answer:

(a). The critical angle for the liquid when surrounded by air is 44.37°

(b). The angle of refraction is 26.17°.

Explanation:

Given that,

Incidence angle = 26.7°

Refraction angle = 18.3°

(a). We need to calculate the refraction of liquid

Using Snell's law

n=\dfrac{\sin i}{\sin r}

Put the value into the formula

n=\dfrac{\sin 26.7}{\sin 18.3}

n=1.43

We need to critical angle for the liquid when surrounded by air

Using formula of critical angle

C=\sin^{-1}(\dfrac{1}{n})

Put the value into the formula

C=\sin^{-1}(\dfrac{1}{1.43})

C=44.37^{\circ}

(b). Given that,

Incidence angle = 37.5°

Speed of light in mineral v=2.17\times10^{8}\ m/s

We need to calculate the index of refraction

Using formula of index of refraction

n=\dfrac{c}{v}

Put the value into the formula

n=\dfrac{3\times10^{8}}{2.17\times10^{8}}

n=1.38

We need to calculate the angle of refraction

Using Snell's law

n=\dfrac{\sin i}{\sin r}

\sin r=\dfrac{\sin i}{n}

Put the value into the formula

\sin r=\dfrac{\sin 37.5}{1.38}

r=\sin^{-1}(\dfrac{\sin 37.5}{1.38})

r=26.17^{\circ}

Hence, (a). The critical angle for the liquid when surrounded by air is 44.37°

(b). The angle of refraction is 26.17°.

3 0
3 years ago
Read 2 more answers
How much heat is needed to raise the temperature of 2 kg of copper from 20º to 30ºC. The specific heat of copper is 390 J/kgºC.
ryzh [129]

Answer:

7800 J

Explanation:

Heat needed = mass of copper x specific heat of copper x change in temperature  

Change in temperature = 30ºC - 20ºC = 10ºC

Specific heat of copper = 390 J/kgºC

Mass of copper = 2 Kg

Substituting the given values in above equation, we get –  

Heat needed = 2 Kg x 390 J/kgºC x 10ºC

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3 0
4 years ago
A cart is pushed at a supermarket for a distance of 30 m South, then 15 m West and finally 5 m West. This entire motion lasts fo
PSYCHO15rus [73]

the speed would have to be somewhere between 1.667 or 1.666 miles per minute.

add 30, 15, 5 together and you will get 50

50 is the total miles traveled

then you multiply 30 by 1.666 and you will get 49.98 but it's still not quite 50 miles

if you multiply 30 by 1.667 and you will get 50.01 but its a little over to miles

i got the 30 from the minutes traveled

anyway that's the best i got for speed

3 0
3 years ago
Read 2 more answers
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