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grigory [225]
3 years ago
11

Ethan drove a 1500 kg car around a circular track with a radius of 75 m. If the magnitude of the centripetal acceleration is 2 m

/s2, what is the car's speed?
A)2.25 m/s
B)20 m/s
C)37.5 m/s
D)150 m/s ​
Physics
1 answer:
Aloiza [94]3 years ago
5 0

Answer:

12.25 m/s

Explanation:

The following data were obtained from the question:

Mass (m) = 1500 Kg

Radius (r) = 75 m

Centripetal acceleration (a) = 2 m/s²

Velocity (v) =?

Centripetal acceleration (a) is related to the velocity (v) and radius (r) according to the following formula:

a = v²/r

Thus, we can obtained the velocity of the car by using the above formula as illustrated below:

Radius (r) = 75 m

Centripetal acceleration (a) = 2 m/s²

Velocity (v) =?

a = v²/r

2 = v²/75

Cross multiply

v² = 2 × 75

v² = 150

Take the square root of both side.

v = √150

v = 12.25 m/s

Thus, the speed of the car is 12.25 m/s.

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Saludos!

Respuesta:

28,64 m/s.

Explicación:

Datos: 

Altura o distancia recorrida: 40 m
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El ejercicio puede ser resuelto facilmente utilizando la siguiente formula, sin embargo es posible realizarlo utilizando formulas diferentes. 

Entonces tenemos que:

Vf ^{2} -Vo ^{2} =2 x g x h

Es importante saber que al estar lanzando el ladrillo hacia abajo, el sentido del movimiento sigue el sentido de la gravedad, es decir es necesario que tomes el valor de la gravedad como positivo (+) y no negativo (-) como normalmente se usa.

Sustituyendo tenemos que:

Vf x^{2} =(6 m/s) ^{2} +(2)x(9,81 m/s ^{2})x(40m) \\ Vf ^{2} =820,8 m^{2} /s ^{2}  \\  \sqrt{Vf ^{2} } = \sqrt{820,8m^{2}/s ^{2}  }  \\ Vf=28,64 m/s

Que tengas un buen día!
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Answer:

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Explanation:

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