Answer:
313.6 m downward
Explanation:
The distance covered by the bullet along the vertical direction can be calculated by using the equation of motion of a projectile along the y-axis.
In fact, we have:
where
y(t) is the vertical position of the projectile at time t
h is the initial height of the projectile
is the initial vertical velocity of the projectile, which is zero since the bullet is fired horizontally
t is the time
a = g = -9.8 m/s^2 is the acceleration due to gravity
We can rewrite the equation as
where the term on the left, 
, represents the vertical displacement of the bullet. Substituting numbers and t = 8 s, we find
So the bullet has travelled 313.6 m downward.
Because the weight of one ball is mg = 147 N, the gravitational force between the two balls is 
or 
parts per billion of the weight.
Answer:
I'm pretty sure the answer is 0 m/s²
Explanation:
The horizontal velocity of the second rock is 5 m/s, so if we pretend air resistance doesn't exist, it will maintain that horizontal velocity, meaning that there is no horizontal acceleration.
The First Quarter Moon is a primary Moon phase when we can see exactly half of the Moon's visible surface illuminated. If it is the left or right half, depends on where you are on Earth.
Velocity = distance/time
v = (35)/(1/2)
v = 70 km/h
60 km/h for 25 minutes
25 minutes = 25/60 hour
distance= velocity * time
d =(60) * (25/60)
d = 25 km
ΔV = { V(initial) - V(final) } / time
v= (70-60) / (45/60)
average velocity = 13.33 km/h
avg veloticy = 3.7 m/s
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