Answer:
45% probability that a randomly selected customer saw the advertisement on the internet or on television
Step-by-step explanation:
We solve this problem building the Venn's diagram of these probabilities.
I am going to say that:
A is the probability that a customer saw the advertisement on the internet.
B is the probability that a customer saw the advertisement on television.
We have that:

In which a is the probability that a customer saw the advertisement on the internet but not on television and
is the probability that the customers saw the advertisement in both the internet and on television.
By the same logic, we have that:

12% saw it on both the internet and on television.
This means that 
20% saw it on television
This means that 
37% of customers saw the advertisement on the internet
This means that 
What is the probability that a randomly selected customer saw the advertisement on the internet or on television

45% probability that a randomly selected customer saw the advertisement on the internet or on television
A. 80
b.100
c.80
d.80
e.20
f. 120
These are all in degrees.
Hope this helps.
Foxeslair
The answer is 2900mg because you have to divide the two numders
Answer:
55,98,27
Step-by-step explanation:
To solve for the angles we must first find y with this equation
3y+5+2y-7=153
We can simplify this
5y-2=153
153+2=155
155/5=31
y=31
We now know y and can plug it into the angles
<A=2y-7
2(31)-7
62-7
55
<A=55
<B=3y+5
3(31)+5
93+5
98
<B=98
Now time for the last angle
Since angle BCA and DCB are next to each other they add up to 180
153+x=180
180-153=27
x=27
<BCA=27
That’s really nice man. I’m sure she’ll love it