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3 years ago

How do I solve #9 & #10

Mathematics

1 answer:

olasank [31]3 years ago

6 0

Do you mean the last two? the 9 and 10 are cut off

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For which fraction pairs would it be useful to use the benchmarks 0, One-half, and 1 to compare? Check all that apply.

koban [17]

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Step-by-step explanation:

thank my answer

pls mark brilinias

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3 years ago

The area of triangle ABC is 3√2 square inches. Find the measure of the acute angle, A, if b = 9 meters and c = 2 meters.

taurus [48]

Answer:

$A\approx 28^{\circ}$

Step-by-step explanation:

Please find the attachment.

We have been given that area of triangle ABC is 3√2 square inches.

$\text{Area}=\frac{1}{2}\text{Base}\times \text{height}$

We know that area of triangle an be found using trigonometry as:

$\text{Area}=\frac{1}{2}\times c\times h$

$\text{sin}(A)=\frac{h}{9}\\h=9\cdot \text{sin}(A)$

$3\sqrt{2}=\frac{1}{2}\times 2\times 9\cdot \text{sin}(A)$

$3\sqrt{2}=9\cdot \text{sin}(A)$

$9\cdot \text{sin}(A)=3\sqrt{2}$

$\text{sin}(A)=\frac{3\sqrt{2}}{9}$

$\text{sin}(A)=\frac{\sqrt{2}}{3}$

Now, we will use inverse sine to find the value of angle A as:

$A=\text{sin}^{-1}(\frac{\sqrt{2}}{3})$

$A=28.1255057^{\circ}$

$A\approx 28^{\circ}$

Therefore, the measure of angle A is approximately 28 degrees.

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