Answer:
The probability that the town has 30 or fewer residents with the illness = 0.00052.
Step-by-step explanation:
So, we have the following set of data or information or parameters given from the question above and they are; the number of people living in that particular society/community/town = 74,000 residents and the proportion of people that the diseases affected = .000215.
The first step to do is to determine the expected number of people with disease. Thus, the expected number of people with disease = 74,000 × .000215 = 15.91.
Hence, the probability that the town has 30 or fewer residents with the illness = 1.23 × 10^-7 × 15.91^30/ 2.65253 × 10^-32 = 0.00052.
Note the formula used in the calculating the probability that the town has 30 or fewer residents with the illness = e^-λ × λ^x/ x!
K+3 3/4=5 2/3-1 1/3
k+3 3/4=4 1/3
lets find the lcm first then multiply both sides by it but first change it to improper fraction
LCM is 12
[k+15/4]=[13/3]12
12k+45=52
12k=7
k=7/12
Nine hundred and seventeen point twenty seven
We have for this case:
For each language we have:
Number of people who speak Spanish:
Spanish = 8 + 4 = 12
Number of people who speak Chinese:
Chinese = 5 + 6 = 11
Number of people who speak both languages:
Both = 3 + 2 = 5
Adding we have:
12 + 11 + 5 = 28
Answer:
28
option A
