sum of sequence Find the sum of 46 + 42 + 38 + ... + (-446) + (-450) is -25,250
<u>Step-by-step explanation:</u>
We need to find sum of sequence : 46 + 42 + 38 + ... + (-446) + (-450)
Given sequence is an AP with following parameters as :
So , Let's calculate how many terms are there as :
⇒
⇒
⇒
⇒
⇒
⇒
Sum of an AP is :
⇒
⇒
⇒
⇒
Therefore , sum of sequence Find the sum of 46 + 42 + 38 + ... + (-446) + (-450) is -25,250
Answer:
m∠PRT = 114°
m∠T = 37°
m∠RPT = 29°
Step-by-step explanation:
This question is incomplete (without a picture) ; here is the picture attached.
In this picture, an airplane is at an altitude 12000 feet.
When the plane is at the point P, pilot can observe two towns at R and T in front of plane.
We have to find the measure of ∠PRT, ∠T and ∠RPT.
Form the figure attached segment PS is parallel to RT and PR is a transverse.
We know that internal angles formed on one side of the parallel lines by a transverse are supplementary.
Therefore, x + 66 = 180
x = 180 - 66 = 114°
∠PRT = x = 114°
m∠RPT = m∠SPR - m∠SPT
= 66 - 37
= 29°
Since m∠PRT + m∠T + m∠RPT = 180°
114 + ∠T + 29 = 180
143 + ∠T = 180
∠T = 180 - 143
∠T = 37°
