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3 years ago

Area of the desk is 1 4/5 square meters the length of the desk is 2 meters what is the width of the desk

1 answer:

5 0

Assuming that the desk simply has a shape of a rectangle, then the formula of the area is simply the product of length and width:

Area = length * width

So the width is:

width = Area / length

width = (9/5 m^2) / (2 m)

width = 0.9 meters

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Ana’s location is -30 feet below the cave entrance, Chilean location is -12 below the cave entrance. Which girl is located farth

sattari [20]

Answer:

Ana

Step-by-step explanation:

4 0

4 years ago

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Prove: If n is a positiveinteger and n2 is divisible by 3, then n is divisible by3.

notka56 [123]

Answer:

If $n^2$ is divisible by 3, the n is also divisible by 3.

Step-by-step explanation:

We will prove this with the help of contrapositive that is we prove that if n is not divisible by 3, then, $n^2$ is not divisible by 3.

Let n not be divisible by 3. Then $\frac{n}{3}$ can be written in the form of fraction $\frac{x}{y}$ , where x and y are co-prime to each other or in other words the fraction is in lowest form.

Now, squaring

$\frac{n^2}{9} = \frac{x^2}{y^2}$

Thus,

$n^2 = \frac{9x^2}{y^2}$

$\frac{n^2}{3} = \frac{3x^2}{y^2}$

It can be clearly seen that the fraction $\frac{3x^2}{y^2}$ is in lowest form.

Hence, $n^2$ is not divisible by 3.

Thus, by contrapositivity if $n^2$ is divisible by 3, the n is also divisible by 3.

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4 years ago

The equation of a circle is given below.

BARSIC [14]

Given:

The equation of the circle is $x^2+(y+4)^2=64$

We need to determine the center and radius of the circle.

Center:

The general form of the equation of the circle is $(x-h)^2+(y-k)^2=r^2$

where (h,k) is the center of the circle and r is the radius.

Let us compare the general form of the equation of the circle with the given equation $x^2+(y+4)^2=64$ to determine the center.

The given equation can be written as,

$(x-0)^2+(y+4)^2=64$

Comparing the two equations, we get;

(h,k) = (0,-4)

Therefore, the center of the circle is (0,-4)

Radius:

Let us compare the general form of the equation of the circle with the given equation $x^2+(y+4)^2=64$ to determine the radius.

Hence, the given equation can be written as,

$x^2+(y+4)^2=8^2$

Comparing the two equation, we get;

$r^2=8^2$

$r=8$

Thus, the radius of the circle is 8

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4 years ago

409,821,735,673 value of the digit 4 in this number.

gulaghasi [49]

409,821,735,673.....the value of the 4 in this number is 400 billion

4 0

3 years ago

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The bases of a trapezoid lie on the lines y=2X +7 and y= 2X -5. Write the equation that contains the midsegment of the trapezoid

ryzh [129]

Given:

The bases of a trapezoid lie on the lines

$y=2x+7$

$y=2x-5$

To find:

The equation that contains the midsegment of the trapezoid.

Solution:

The slope intercept form of a line is

$y=mx+b$

Where, m is slope and b is y-intercept.

On comparing $y=2x+7$ with slope intercept form, we get

$m_1=2,b_1=7$

On comparing $y=2x-5$ with slope intercept form, we get

$m_2=2,b_2=-5$

The slope of parallel lines are equal and midsegment of a trapezoid is parallel to the bases. So, the slope of the bases line and the midsegment line are equal.

$m=m_1=m_2=2$

The y-intercept of one base is 7 and y-intercept of second base is -5. The y-intercept of the midsegment is equal to the average of y-intersects of the bases.

$b=\dfrac{b_1+b_2}{2}$