The diagram is in the picture attached.
Options are:
A) 32 °C
B) 70 °C
C) 92 °C
D) 100 °C
In order to find the value required, you need to look at the diagram and follow these steps:
1) search for the value of 70 kPa on the y-axis;
2) move on a horizontal line towards the right until you reach the line D;
3) move on a vertical line down, towards the x-axis;
4) read at what value of °C you are at.
Doing so, you can see that you are at a value a little bit above 90 °C (see picture).
Hence, the correct answer is
C) 92°C.
Answer:
Nuestro mejor amigo escuchará la música más rápido a una temperatura de 36 ºC (309.15 K)
Explanation:
Supongase que el aire se comporta como un gas ideal y que experimenta un proceso adiabático, entonces la velocidad del sonido (), medida en metros por segundo, queda traducida en la siguiente fórmula:
(1)
Donde:
- Coeficiente de dilatación térmica, sin unidad.
- Coeficiente universal de los gases ideales, medido en kilogramo-metros cuadrados por mol-Kelvin-segundo cuadrado.
- Temperatura, medida en Kelvin.
- Masa molar, medida en kilogramos por mol.
Como se puede ver, la velocidad del sonido es directamente proporcional a la raíz cuadrada de la temperatura. Por tanto, nuestro mejor amigo escuchará la música más rápido a una temperatura de 36 ºC (309.15 K)
I'm going to make an assumption here. The speed of the wave is 343m/s = c.
The equation for speed of a wave is c = λf. λ: wavelength f: frequency
Substituting known values, we get 343m/s = λ(784Hz)
λ = 0.4375m
Answer:
12 cm and 0.4
Explanation:
f = - 20 cm, u = - 30 cm
Let v be the position of image and m be the magnification.
Use lens equation
1 / f = 1 / v - 1 / u
- 1 / 20 = 1 / v + 1 / 30
1 / v = - 5 / 60
v = - 12 cm
m = v / u = - 12 / (-30) = 0.4
Answer:
a). The potential is highest at the center of the sphere
Explanation:
We k ow the potential of a non conducting charged sphre of radius R at a point r < R is given by
Therefore at the center of the sphere where r = 0
Now at the surface of the sphere where r = R
Now outside the sphere where r > R, the potential is
This gives the same result as the previous one.
As
Thus, the potential of the sphere is highest at the center.