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Contact [7]
3 years ago
10

I REALLY NEED HELP PLEASE!!! CAN SOMEONE ANSWER THIS? At 0 ºC, some amount of energy is required to change 1 kg of water from a

solid into a liquid. If you had a 2 kg piece of ice, what effect would this have on the amount of thermal energy required to change the water from a solid to a liquid? A)It would require energy to be removed from the 2 kg piece of ice. The larger piece of ice already has more total energy than the smaller piece of ice, so energy must be removed for the ice to become liquid. B)It would require less energy to change solid water into liquid water because the energy would spread through the ice more quickly and the ice already has a larger total amount of energy because it is larger than a 1 kg piece of ice. C)It would require more energy to change solid water into liquid water because there are more molecules in this larger piece of ice. D)It would still require the same amount of energy to change solid water into liquid water because the entire piece of ice would still gain the same amount of energy in each case.
Physics
2 answers:
Nezavi [6.7K]3 years ago
8 0

Answer:

C)It would require more energy to change solid water into liquid water because there are more molecules in this larger piece of ice.

Charra [1.4K]3 years ago
4 0

Explanation:

c. it would require more energy to change ........

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What happens to the temperature during an endothermic reaction? ANSWERS; The temperature stays constant. The temperature will de
EleoNora [17]

Answer:

The temperature will decrease (get colder).

Explanation:

Enthalpy changes are heat changes accompanying physical and chemical changes. The enthalpy change is the difference between the sum of the heat contents of products and the sum of heat contents of reactants.

  • For an endothermic change, heat is absorbed for the reaction.
  • The surrounding becomes colder at the end of the reaction and so is the reaction itself.
  • The right choice is that the temperature will decrease.
6 0
3 years ago
Suppose the ski patrol lowers a rescue sled carrying an injured skier, with a combined mass of 97.5 kg, down a 60.0-degree slope
Kitty [74]

a. 1337.3 J work, in joules, is done by friction as the sled moved 28 m along the hill.

b.21,835 J work, in joules, is done by the rope on the sled this distance.

c. 23,170 J   the work, in joules done by the gravitational force on the sled d. The net work done on the sled, in joules is 43,670 J.

       

<h3>What is friction work?</h3>

The work done by friction is the force of friction times the distance traveled times the cosine of the angle between the friction force and displacement

a. How much work is done by friction as the sled moves 28m along the hill?

ans. We use the formula:

friction work = -µ.mg.dcosθ

  = -0.100 * 97.5 kg * 9.8 m/s² * 28 m * cos 60

= -1337.3 J

-1337.3 J work, in joules, is done by friction as the sled moved 28 m along the hill.

b. How much work is done by the rope on the sled in this distance?

We use the formula:

Rope work = -m.g.d(sinθ - µcosθ)

rope work = - 97.5 kg * 9.8 m/s² * 28 m (sin 60 – 0.100 * cos 60)

                     = 26,754 (0.816)

                     = 21,835 J

21,835 J work, in joules, is done by the rope on the sled this distance.

c.  What is the work done by the gravitational force on the sled?

By using  the formula:

Gravity work = mgdsinθ

                    = 97.5 kg * 9.8 m/s² * 28 m * sin 60

                    = 23,170 J

23,170 J   the work, in joules done by the gravitational force on the sled .

       

D. What is the total work done?

By adding all the values

work done =  -1337.3 + 21,835 + 23,170

                 = 43,670 J

The net work done on the sled, in joules is 43,670 J.

Learn more about friction work here:

brainly.com/question/14619763

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4 0
2 years ago
Based on the diagram of a roller coaster car on a roller coaster track, what statement is true?
Vsevolod [243]

Answer:

B) The car at point C has less kinetic energy than the car at point B.

Explanation:

We have two types of energy involved in this situation:

- Gravitational potential energy: this is the energy related to the heigth of the car, and it is given by U=mgh, where m is the mass of the car, g is the gravitational acceleration, and h is the heigth of the car. The potential energy is higher when the car is located higher above the ground.

- Kinetic energy: this is the energy due to the motion of the car, and it is given by K=\frac{1}{2}mv^2, where m is the mass of the car and v is its speed. The kinetic energy is higher when the speed of the car is higher.

- The law of conservation of energy states that the total mechanical energy of the car (sum of potential energy and kinetic energy: E=U+K) is constant). This implies that when the car is at a higher point, the kinetic energy is less (because U is larger, so K must be smaller), while when the car is at a lower point, the kinetic energy is larger.

- Based on what we have written so far, we can conclude that the correct statement is:

B) The car at point C has less kinetic energy than the car at point B.

Because the car at point C is located at a higher point than point B, so the car at point C has larger potential energy than at point B, which implies that car at point C has less kinetic energy than the car at point B.

6 0
4 years ago
Banked Curves: A 600-kg car is going around a banked curve with a radius of 110 m at a steady speed of 24.5 m/s. What is the app
Aleks04 [339]

The angle of baking from the calculation is obtained as 30°.

<h3>What is banking?</h3>

The term banking refers to a means of preventing vehicles from skidding off the road at curves.

We know that the banking angle is obtained from;

θ = tan-1(v^2/rg)

v = 24.5 m/s

r = 110 m

g = 9.8 m/s^2

θ = tan-1(25^2/9.8 * 110)

θ = tan-1(625 /1078)

θ = 30°

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8 0
2 years ago
A law of motion that states that an object at rest stays at rest and one in motion stays in motion
antiseptic1488 [7]

Answer:

Newton's first law of motion

Explanation:

It's states that "An object at rest stays at rest and an object in motion stays in motion with the same speed and in the same direction unless acted upon by an unbalanced force"

4 0
3 years ago
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