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ExtremeBDS [4]
4 years ago
13

The distance between planets varies as they move in their orbits. The minimum distance from the Earth to Mars is about 0.35 AU.

About how many kilometers is that?
Physics
2 answers:
Natalija [7]4 years ago
6 0

Answer:

c on edge

Explanation:

Alina [70]4 years ago
5 0

Answer:

52,360,000km

Explanation:

To solve this problem you use a conversion factor.

By taking into account that 1UA = 1.496*10^{8}km you obtain:

0.35UA*\frac{1.496*10^{8}km}{1UA}=52,360,000km

hence, 0.35UA is about 52,360,000km. This is the least distance between Mars and Earth

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When an object is moving with uniform circular motion, the centripetal acceleration of the object d. is directed toward the center of motion.

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When the Sun is directly overhead, the intensity of sunlight reaching the ground is about 1000 W/m^{2} 2 . The Earth has a radiu
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The total power associated with sunlight shining on the Earth is 8.04 × 10^10W

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In proton beam therapy, a beam of high-energy protons is used to kill cancerous cells in a tumor. In one system, the beam, which
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The number of protons that strike the tumor each second is 1.75 \times 10^8 protons.

<u>Given the following data:</u>

  • Energy of proton = 2.8 \times 10^{-11} Joules.
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  • Energy of total dose = 3.4 \times 10^{-3} Joules.

<u>Scientific data:</u>

  • Charge of proton = 1.602 \times 10^{-19} C.

To determine the number of protons that strike the tumor each second:

<h3>How to determine the number of protons.</h3>

Mathematically, the quantity of charge per unit time is given by this formula:

Q =It=Ne\\\\N = \frac{Q}{e}

<u>Where:</u>

  • N is the number of protons.
  • t is the time measured in seconds.
  • I is the current.
  • e is the charge of protons.

Substituting the parameters into the formula, we have;

N=\frac{2.8 \times 10^{-11} }{1.602 \times 10^{-19}} \\\\N = 1.75 \times 10^{8}protons.

Read more on charges here: brainly.com/question/14372859

8 0
3 years ago
If a car has an initial velocity of 20 m/s and accelerates at 2.0 m/s² for 100 m, what is its final velocity?
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Answer:

28.28 ms-1

Explanation:

v² = u² + 2as

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v = 28.28 ms-1

8 0
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QUESTION 1
Sveta_85 [38]

distance from the Sun of 2.77 astronomical units or about 414 million km 257 million miles and orbiting period of 4.62 years

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3 years ago
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