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ExtremeBDS [4]
3 years ago
13

The distance between planets varies as they move in their orbits. The minimum distance from the Earth to Mars is about 0.35 AU.

About how many kilometers is that?
Physics
2 answers:
Natalija [7]3 years ago
6 0

Answer:

c on edge

Explanation:

Alina [70]3 years ago
5 0

Answer:

52,360,000km

Explanation:

To solve this problem you use a conversion factor.

By taking into account that 1UA = 1.496*10^{8}km you obtain:

0.35UA*\frac{1.496*10^{8}km}{1UA}=52,360,000km

hence, 0.35UA is about 52,360,000km. This is the least distance between Mars and Earth

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Explanation:

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WHY does an acceleration cause velocity to increase
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An object is located 70 cm from a concave mirror with a focal length of 15 cm. What is the image
Stels [109]

(a) The distance of the image formed by the concave mirror is 19.1 cm.

(b) The image formed is diminished and real.

<h3>Image distance </h3>

The distance of the image formed by the concave mirror is calculated as follows;

1/f = 1/v + 1/u

1/v = 1/f - 1/u

1/v = 1/15 - 1/70

1/v = 0.05238

v = 1/0.05238

v = 19.1 cm

The image distance is smaller than object distance, thus the image formed is diminished and real.

Learn more about concave mirror here: brainly.com/question/13164847

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2 years ago
A railroad car of mass 2,000 kg traveling at a velocity v = 10 m/s is stopped at the end of the tracks by a spring-damper system
Murrr4er [49]
Stopped at the end of the tracks by a spg-damper system, as shown in fig. 1
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3 years ago
you push a shopping cart with 2 packs of water bottles. you stop the cart and add two more packs. you push the cart again. does
HACTEHA [7]

Answer:

Yes

Explanation:

The cart will definitely behave differently because more weight is added to it.

In order to successfully push a cart, the applied force must exceed the force of the weight of the cart along with its constituents and the frictional force between the tyres and the floor.

<em>When more weights are added (the 2 packs of water bottles), it means that more force would be needed to overcome the opposing forces to the movement of the cart in order to successfully push the cart again.</em>

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