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Andrew [12]
3 years ago
5

A 0.5 kg ball moves in a circle that is 0.4 m in radius at a speed of 4.0 m/s. Calculate the centripetal force exerted on the ba

ll.

Physics
1 answer:
sladkih [1.3K]3 years ago
5 0
M = 0.5 kg, the mass of the ball
r = 0.4 m. the radius from the center of the circle to the ball
v = 4.0 m/s, the tangential velocity of the ball as the ball rotates
      counterclockwise about the center of the circle.

Refer to the diagram shown below.

By definition, the centripetal acceleration of the ball is
a = v²/r = (4 m/s)²/(0.4 m) = 40 m/s²
The centripetal force exerted on the ball is
F = m*a =  (0.5 kg)*(40 m/s²) = 20 N

Answer:  20 N

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Answer:

Explanation:

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Diagram of gravitational forces between two spheres

Let’s examine this formula a bit more closely.

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m_1m  

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​  

m, start subscript, 1, end subscript and m_2m  

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m, start subscript, 2, end subscript are the masses of objects 1 and 2. As we saw with Newton’s second law (\vec{F} = M\vec{A}  

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\hat{r}  

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r^2r  

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r, squared refers to the distance between the two objects squared. Let’s take a moment to think about this a bit more. With everything on the top of the formula—G, m_1m  

1

​  

m, start subscript, 1, end subscript, m_2m  

2

​  

m, start subscript, 2, end subscript—the bigger its value, the stronger the force. Big mass, big force. Big G, big force. Now, when we divide by something, we have the opposite. The strength of the force is inversely proportional to the distance squared. The farther away an object is, the weaker the force; the closer, the stronger.

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Given these assumptions, we want to compute a PVector force, the force of gravity. We’ll do it in two parts. First, we’ll compute the direction of the force \hat{r}  

r

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we need to solve the quadratic equation:

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3 years ago
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