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Andrew [12]
3 years ago
5

A 0.5 kg ball moves in a circle that is 0.4 m in radius at a speed of 4.0 m/s. Calculate the centripetal force exerted on the ba

ll.

Physics
1 answer:
sladkih [1.3K]3 years ago
5 0
M = 0.5 kg, the mass of the ball
r = 0.4 m. the radius from the center of the circle to the ball
v = 4.0 m/s, the tangential velocity of the ball as the ball rotates
      counterclockwise about the center of the circle.

Refer to the diagram shown below.

By definition, the centripetal acceleration of the ball is
a = v²/r = (4 m/s)²/(0.4 m) = 40 m/s²
The centripetal force exerted on the ball is
F = m*a =  (0.5 kg)*(40 m/s²) = 20 N

Answer:  20 N

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Question:

A particle moving along the x-axis has a position given by x=(24t - 2.0t³)m, where t is measured in s. What is the magnitude of the acceleration of the particle at the instant when its velocity is zero

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ycow [4]

Answer:

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