A 0.5 kg ball moves in a circle that is 0.4 m in radius at a speed of 4.0 m/s. Calculate the centripetal force exerted on the ba
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1 answer:
M = 0.5 kg, the mass of the ball
r = 0.4 m. the radius from the center of the circle to the ball
v = 4.0 m/s, the tangential velocity of the ball as the ball rotates
counterclockwise about the center of the circle.
Refer to the diagram shown below.
By definition, the centripetal acceleration of the ball is
a = v²/r = (4 m/s)²/(0.4 m) = 40 m/s²
The centripetal force exerted on the ball is
F = m*a = (0.5 kg)*(40 m/s²) = 20 N
Answer: 20 N
r = 0.4 m. the radius from the center of the circle to the ball
v = 4.0 m/s, the tangential velocity of the ball as the ball rotates
counterclockwise about the center of the circle.
Refer to the diagram shown below.
By definition, the centripetal acceleration of the ball is
a = v²/r = (4 m/s)²/(0.4 m) = 40 m/s²
The centripetal force exerted on the ball is
F = m*a = (0.5 kg)*(40 m/s²) = 20 N
Answer: 20 N
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Answer:
Magnetic force, F = 0.24 N
Explanation:
It is given that,
Current flowing in the wire, I = 4 A
Length of the wire, L = 20 cm = 0.2 m
Magnetic field, B = 0.6 T
Angle between force and the magnetic field, θ = 30°. The magnetic force is given by :
F = 0.24 N
So, the force on the wire at an angle of 30° with respect to the field is 0.24 N. Hence, this is the required solution.
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