Answer: 
Explanation:
Given
Volume of air 
Temperature of air 
Increase in temperature 
Specific heat for diatomic gas is 
Energy required to increase the temperature is
![\Rightarrow Q=nC_pdT\\\\\Rightarrow Q=n\times \dfrac{7R}{2}\times \Delta T\\\\\Rightarrow Q=\dfrac{7}{2}nR\Delta T\\\\\Rightarrow Q=\dfrac{7}{2}\times \dfrac{PV}{T}\times \Delta T\quad [\text{using PV=nRT}]](https://tex.z-dn.net/?f=%5CRightarrow%20Q%3DnC_pdT%5C%5C%5C%5C%5CRightarrow%20Q%3Dn%5Ctimes%20%5Cdfrac%7B7R%7D%7B2%7D%5Ctimes%20%5CDelta%20T%5C%5C%5C%5C%5CRightarrow%20Q%3D%5Cdfrac%7B7%7D%7B2%7DnR%5CDelta%20T%5C%5C%5C%5C%5CRightarrow%20Q%3D%5Cdfrac%7B7%7D%7B2%7D%5Ctimes%20%5Cdfrac%7BPV%7D%7BT%7D%5Ctimes%20%5CDelta%20T%5Cquad%20%5B%5Ctext%7Busing%20PV%3DnRT%7D%5D)
Insert the values
Compared to energy-flow in ecosystems, the flow of matter <span>reflects conservation and recycling.
For example, let's take a look at the food chain system. Every time an organism is consumed by another organism, the energy that is given to the eater is only about 10% of the total existing energy
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Mostly GPE and a little KE since the ball is high up (GPE) and it's also moving (KE) but not as much as it had when you first threw it
- In order to achieve the desired resistance under the given circumstances, we would connect two 50 Ohms resistors in parallel and then connect it in series with the 20 Ohms resistors.
- In order to get a 35 Ohms resistance under the given circumstances, we would connect two 50 Ohms resistors in parallel and then connect it in series with two 20 Ohms resistors that are connected in parallel.
<h3>How to achieve the desired resistance under these circumstances?</h3>
In order to achieve the desired resistance under the given circumstances, we would connect two 50 Ohms resistors in parallel and then connect it in series with the 20 Ohms resistors.
Mathematically, the total equivalence resistance of two resistors that are connected in parallel is given by:
1/Rt = 1/R₁ + 1/R₂
1/Rt = 1/50 + 1/50
1/Rt = 2/50
1/Rt = 1/25
Rt = 25 Ohms.
Next, we would connect this 25 Ohms resistor in series with the 20 Ohms resistor:
R₃ = 20 + Rt
R₃ = 20 + 25
R₃ = 45 Ohms.
<h3>Part B.</h3>
In order to get a 35 Ohms resistance under the given circumstances, we would connect two 50 Ohms resistors in parallel and then connect it in series with two 20 Ohms resistors that are connected in parallel.
1/Rt = 1/R₁ + 1/R₂
1/Rt = 1/50 + 1/50
1/Rt = 2/50
1/Rt = 1/25
Rt = 25 Ohms.
1/R't = 1/R₁ + 1/R₂
1/R't = 1/20 + 1/20
1/R't = 2/20
1/R't = 1/10
R't = 10 Ohms.
Next, we would connect the 25 Ohms resistor in series with the 10 Ohms resistor:
R₃ = 10 + Rt
R₃ = 10 + 25
R₃ = 35 Ohms.
Read more on resistors in parallel here: brainly.com/question/15121871
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Complete Question:
You need a 45-ω resistor, but the stockroom has only 20-ω and 50-ω resistors.
(a) How can the desired resistance be achieved under these circumstances?
(b) What can you do if you need a 35-ω resistor?
