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3 years ago

1 What happens when sodium reacts with chlorine to form sodium chloride?

Chemistry

1 answer:

N76 [4]3 years ago

3 0

Answer:

When a sodium atom transfer over to a chlorine atom it forms a sodium cation and a chloride anion.

Explanation:

During that time both of the ions would have completely valence shells and energy wise are more stable, the reaction is usually VERY exothermic (Release of heat) which usually produces a bright yellow light.

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What three processes cause fireworks to emit light?

N76 [4]

Pyrotechnic compositions emit light by three basic processes - incandescence (blackbody radiation) atomic emission, and molecular emission.

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3 years ago

Which of the following structures provides support and movement ?

quester [9]

Answer:

The answer is C.

Explanation:

This is because you wouldn't be able to function without your lungs and spine. So therefore the answer would have to be "C".

8 0

3 years ago

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A sample of sulfur hexafluoride gas occupies a volume of 5.10 L at 198 ºC. Assuming that the pressure remains constant, what tem

Ludmilka [50]

Answer:

When the volume will be reduced to 2.50 L, the temperature will be reduced to a temperature of 230.9K

Explanation:

Step 1: Data given

A sample of sulfur hexafluoride gas occupies a volume of 5.10 L

Temperature = 198 °C = 471 K

The volume will be reduced to 2.50 L

Step 2 Calculate the new temperature via Charles' law

V1/T2 = V2/T2

⇒with V1 = the initial volume of sulfur hexafluoride gas = 5.10 L

⇒with T1 = the initial temperature of sulfur hexafluoride gas = 471 K

⇒with V2 = the reduced volume of the gas = 2.50 L

⇒with T2 = the new temperature = TO BE DETERMINED

5.10 L / 471 K = 2.50 L / T2

T2 = 2.50 L / (5.10 L / 471 K)

T2 = 230.9 K = -42.1

When the volume will be reduced to 2.50 L, the temperature will be reduced to a temperature of 230.9K

8 0

3 years ago

The density of the solid phase of a substance is 0.90 g/cm3 and the density of the liquid phase is 1.0 g/cm3. A large increase i

aliina [53]

Answer:

it is c

Explanation:

5 0

4 years ago

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For the following reaction, 7.43 grams of methane (CH4) are allowed to react with 27.6 grams of carbon tetrachloride. methane (C

NikAS [45]

Answer:

30.4 grams of CH2Cl2 will be formed

Explanation:

Step 1: data given

Mass of methane = 7.43 grams

Molar mass of methane (CH4) = 16.04 g/mol

Mass of CCl4 = 27.6 grams

Molar mass of CCl4 = 153.82 g/mol

Step 2: The balanced equation

CH4 + CCl4 → 2CH2Cl2

Step 3: Calculate moles

Moles = mass / molar mass

Moles methane = mass methane / molar mass methane

Moles methane = 7.43 grams / 16.04 g/mol

Moles methane = 0.463 moles

Moles CCl4 = 27.6 grams / 153.82 g/mol

Moles CCl4 = 0.179 moles

Step 4: Calculate limiting reactant

For 1 mol CH4 we need 1 mol CCl4 to produce 2 moles CH2Cl2

CCl4 is the limiting reactant. It will completely be consumed. (0.179 moles). Ch4 is in excess. There will react 0.179 moles. There will remain 0.463 - 0.179 = 0.284 moles

Step 5: Calculate moles CH2Cl2

For 1 mol CH4 we need 1 mol CCl4 to produce 2 moles CH2Cl2

For 0.179 moles CCl4 we'll have 2*0.179 = 0.358 moles CH2Cl2

Step 6: Calculate mass CH2Cl2

Mass CH2Cl2 = 0.358 moles* 84.93 g/mol

Mass CH2Cl2 = 30.4 grams

30.4 grams of CH2Cl2 will be formed

3 0

4 years ago