What is the pH of a 0.028M solution (pH= -log(M)) A) 3.56 B) 2.88 C) 1.55 D) 1
1 answer:
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Answer:
T₂ = 19.95°C
Explanation:
From the law of conservation of energy:
where,
mc = mass of copper = 37.2 g
Cc = specific heat of copper = 0.385 J/g.°C
mw = mass of water = 188 g
Cw = specific heat of water = 4.184 J/g.°C
ΔTc = Change in temperature of copper = 99.8°C - T₂
ΔTw = Change in temperature of water = T₂ - 18.5°C
T₂ = Final Temperature at Equilibrium = ?
Therefore,
<u>T₂ = 19.95°C</u>