Answer:
II. The reaction is exothermic.
III. The enthalpy term would be different if the water formed was gaseous.
Explanation:
For the reaction:
C₂H₅OH(l) + 3O₂(g) → 2CO₂(g) + 3H₂O(l)
The ΔH is -1.37×10³ kJ. As the change in enthalpy is <0,<em> II. The reaction is exothermic.</em>
The ΔH formation of a compound is different if the chemical is in liquid or gaseous phase. For that reason: <em>III. The enthalpy term would be different if the water formed was gaseous.</em>
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I hope it helps!
Fully donating an electron results in an ionic bond, so A is the correct answer.
In comparison, B, a hydrogen bond, is a bond that forms between an H in one compound and an O, N, or F in another. It is among the strongest of intermolecular forces, while ionic/covalent bonds are intramolecular.
C, a covalent bond, is a bond that forms when atoms share electrons instead of donating them.
Answer:
Both have a pH greater than 7, but NH₃ has a lower pH than KOH.
Explanation:
- Both of NH₃ and KOH are bases (can produce OH⁻), so both have a pH greater than 7.
- NH₃ is considered as a weak base (not completely ionized), while KOH is a strong base (completely ionized).
- If both NH₃ an KOH has the same concentration, KOH produces OH⁻ higher than that of NH₃.
- So, NH₃ has a lower pH than KOH.
- Thus the right choice is:
<em>Both have a pH greater than 7, but NH₃ has a lower pH than KOH.</em>
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hydrogen (H2),and oxygen (O2),, that is the answer