Answer:
4th graph
6th graph
3rd graph
Step-by-step explanation:
Linear = y = x + 3
it is 4th graph
when you substitute x = 0 y is 3
and when y = 0 x is -3
Quadratic = y = 3x^2
It is 6th graph
for both positive and negative values of x, y is rapidly increasing
Exponential = y = 3^x
it is 3rd graph
for x = 0 y value is 1 because 3^0 = 1
for positive values of x, y is exponentially rising
for negative values of x it is nearly almost touches zero
imagine 135/5
which = 27
Emma has 27 of her 5 pence coins
Answer:
Both are irrational
Step-by-step explanation:
is a trick as it does simplify to
, but that is irrational
Answer:
<u><em>k = 0.2645</em></u>
Step-by-step explanation:
Given model:
y = 4070 
y = no. of hits website received = 9000 (in 3rd month)
t= no. of months website has been operational = 3
put in the above equation:
9000 = 4070 
= 
=
<u><em>Taking natural logarithm on both sides, we get:</em></u>
=
= 3k ln<em>e</em>
ln<em>e</em>=1
= 3k
or k = 

k =
(0.7936)
<em>k = 0.2645</em>
<em />
Answer:
fffgfdfgee
Step-by-step explanation: