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2 years ago

In what order should Jerome put these models to show the development from the earliest model of the atomto the most recent one ?

Physics

2 answers:

Brilliant_brown [7]2 years ago

6 0

iren [92.7K]2 years ago

4 0

Y X Z W i just did the test and i can confirm this is correct.

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How many significant figures does each of the following numbers have?

Ivan

Pls specify and I can help it really does not make scence?

6 0

2 years ago

A piston–cylinder assembly contains 5.0 kg of air, initially at 2.0 bar, 30 oC. The air undergoes a process to a state where th

vlada-n [284]

Answer:

Explanation:

The process is isothermic, as P V = constant .

work done = 2.303 n RT log P₁ / P₂

= 2.303 x 5 / 29 x 8.3 x 303 log 2 / 1 kJ

= 300.5k J

This energy in work done by the gas will come fro heat supplied as internal energy is constant due to constant temperature.

heat supplied = 300.5k J

specific volume is volume per unit mass

v / m

pv = n RT

pv = m / M RT

v / m = RT / p M

specific volume = RT / p M

option B is correct.

5 0

3 years ago

Which of the following objects has the greatest inertia?

sdas [7]

I'm guessing D. toothpick, but i might be wrong.

6 0

3 years ago

Read 2 more answers

A 130 g bullet is fired from a rifle having a barrel 0.560 m long. Assuming the origin is placed where the bullet begins to move

Helen [10]

Answer:

Explanation:

Given

mass of bullet $m=130 gm$

Length of barrel $L=0.56 m$

Force $F=11000+13000x-28000x^2$

Work done $W=\int_{x_0}^{x_f}Fdx$

$W_1=\int_{0}^{0.56}\left ( 11000+13000x-28000x^2\right )dx$

$W_1=\left [ 11000x+6500x^2-\frac{28000}{3}x^3\right ]_0^{0.56}$

$W_1=6160+2038.4-1639.082=6599.318 J\approx 6.599 kJ$

(b) When barrel is 1 m long

$W_2=\int_{0}^{1}\left ( 11000+13000x-28000x^2\right )dx$

$W_2=\left [ 11000x+6500x^2-\frac{28000}{3}x^3\right ]_0^{1}$

$W_2=11000+6500-\frac{28000}{3}$

$W_2=8166.66 kJ$

$\frac{W_2}{W_1}=\frac{8166.66}{6599.318}=1.237 kJ$

4 0

3 years ago

Read 2 more answers

A resistor with an unknown resistance is connected in parallel to a 13 Ω resistor. When both resistors are connected in parallel

larisa86 [58]

Answer:

R2 = 10.31Ω

Explanation:

For two resistors in parallel you have that the equivalent resistance is:

$\frac{1}{R_{eq}}=\frac{1}{R_1}+\frac{1}{R_2}\\\\$ (1)

R1 = 13 Ω

R2 = ?

The equivalent resistance of the circuit can also be calculated by using the Ohm's law:

$I=\frac{V}{R_{eq}}\\\\R_{eq}=\frac{V}{I}$ (2)

V: emf source voltage = 23 V

I: current = 4 A

You calculate the Req by using the equation (2):

$R_{eq}=\frac{23V}{4A}=5.75\Omega$

Now, you can calculate the unknown resistor R2 by using the equation (1):

$\frac{1}{R_2}=\frac{1}{R_{eq}}-\frac{1}{R_1}\\\\R_2=\frac{R_{eq}R_1}{R_1-R_{eq}}\\\\R_2=\frac{(5.75\Omega)(13\Omega)}{13\Omega-5.75\Omega}=10.31\Omega$

hence, the resistance of the unknown resistor is 10.31Ω

8 0

3 years ago

Read 2 more answers