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DIA [1.3K]
2 years ago
7

A 60.0-kg skater begins a spin with an angular speed of 6.0 rad/s. By changing the position of her arms, the skater decreases he

r moment of inertia to one-half its initial value. What is the skater's final angular speed
Physics
1 answer:
juin [17]2 years ago
7 0

The skater's final angular speed is equal to 12 rad/s.

When implemented to angular momentum, the regulation of conservation means that the momentum of a rotating item is no longer exchanged until some form of external torque is carried out. Torque, in this sense, can check with any outside pressure that acts upon the object for the purpose to twist or rotate.

The law of conservation of angular momentum states that once no external torque acts on an item, no trade of angular momentum will occur. The angular momentum of a machine is conserved as long as there may be no net external torque performing on the machine.

In angular kinematics, the conservation of angular momentum refers back to the tendency of a device to keep its rotational momentum inside the absence of outside torque. For a round orbit, the system for angular momentum is (mass) ×(pace) ×(radius of the circle): (angular momentum) = m × v × r.

Learn more about angular momentum here brainly.com/question/7538238

#SPJ4

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Which of the following statements does not correctly describe a harmonic plane wave traveling in some medium.
Nostrana [21]

Answer:

Incorrect statement is (b).

Explanation:

Option (a) : There is an inverse relation between the time and the frequency. The time taken depends on the frequency of the number of oscillations. Statement 1 is correct i.e. the time taken by any point of the wave to make one complete oscillation does not depend on the amplitude.

Option (b) : Speed of a wave is given by the product of its frequency and wavelength. It is not necessary that doubling the wavelength of the wave will halve its frequency as speed depends on the medium.

Option (c) : Doubling the amplitude has no effect on on the wavelength as amplitude does not depends on its wavelength.

Option (d) : Since, v=f\times \lambda

Speed is directly proportional to the frequency and wavelength. So, doubling the frequency of the wave will double its speed. So, the incorrect statement is (b).

3 0
3 years ago
1. If an object on a horizontal frictionless surface is attached to a spring, displaced, and then released. It will oscillate. I
AURORKA [14]

Answer: a) 0.12m; b) 1,6 s; c) 0.625 1/s

Explanation: The simple harmonic movement can be described by a sin or cosine function  in time.

This can be in the form:

X(t)= A Sin/Cos (wt+φ) where φ is initial phase o position at t=0

w the angular frequency are related to the frequency (f) as 2Pif

and f=1/T period of oscillating

3 0
3 years ago
An Object is moving due south at 16 m/s, when a force accelerates it at 4m/s in a southerly direction. How long will it take for
N76 [4]

Answer:

Time taken to accelerate to 48 m/s =  8 seconds

Explanation:

Initially the object is moving south at = 16 m/s

So, initial velocity of the object = 16 m/s

Acceleration caused by the force = 4 m/s^2

Final velocity towards south = 48 m/s

Using equation of motions:

v_f=v_i+at

where

v_f\rightarrow final velocity

v_i\rightarrow initial velocity

a\rightarrow acceleration

t\rightarrow time

Plugging in values.

48=16+(4)t

48=16+4t

Subtracting both sides by 16

48-16=16+4t-16

32=4t

Dividing both side by 4.

\frac{32}{4}=\frac{4t}{4}

8=t

∴ t=8

Time taken to accelerate to 48 m/s =  8 seconds

6 0
3 years ago
Centrifugal force increases with
belka [17]

Centrifugal force is not a real force. 

When you move around a curve, there IS a real force pulling you
around the curve.  Since your body wants to go straight, it feels as if
there's a force trying to pull you away from the curve.  But there isn't.

That feeling of a force is greater when your speed around the curve
is greater, or when the curve is tighter, i.e. smaller radius.

8 0
3 years ago
Read 2 more answers
a 55.0 kg person having a denity of 1010 kg/m^3 is underwater. What is the net force acting on the person?
bija089 [108]

Answer:

The net force acting on the person is 5.34 N acting upwards

Explanation:

The information given are;

Mass of the person = 55.0 kg

Density of the person = 1010 kg/m³

Body volume of the person = Mass/Density = 55/1010 = 0.0545 m³

Weight of the person = Mass × Gravity = 55 × 9.81 = 539.55 N↓

Where the density of water = 1000 kg/m³, we have;

Upthrust = weight of the water displaced = Mass of the water displaced × Gravity

Mass of the water displaced = Density of water × Volume of the water

Mass of the water displaced = Density of water × Body volume of the person

                                                = 1000 × 0.0545 = 54.5 kg

The Upthrust = 54.5 × 9.81 = 534.21 N↑

Given that the net force, F_{Net} acting is the sum of the mass of forces acting  on the person which are the weight acting downward and the upthrust acting upwards

We have;

F(Net) = 534.21↑ - 539.55↓ = 5.34 N↑

The net force acting on the person = 5.34 N upwards.

6 0
3 years ago
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