Answer:
m<V = 11.2 degrees
Step-by-step explanation:
In ΔUVW, the measure of ∠W=90°, UV = 6.2 feet, and WU = 1.2 feet.
From the triangle;
UV = hypotenuse = 6.2feet
WU = opposite = 1.2feet
Required
m<V
Using the SOH CAH TOA identity
sin m<V = opp/hyp
sin m<V = WU/UV
sin m<V = 1.2/6.2
sin m<V = 0.1936
m<V = arcsin(0.1936)
m<V = 11.16
m<V = 11.2 degrees ((to the nearest tenth of a degree)
Answer:
60
Step-by-step explanation:
We have been given the matrix;
![\left[\begin{array}{ccc}5&8\\-5&4\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D5%268%5C%5C-5%264%5Cend%7Barray%7D%5Cright%5D)
For a 2-by-2 matrix, the determinant is calculated as;
( product of elements in the leading diagonal) - (product of elements in the other diagonal)
determinant = ( 5*4) - (8*-5)
= 20 - (-40) = 60
Answer:
7
Step-by-step explanation:
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The answer is 42 bc I really do not know trying to get points!
