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Elanso [62]
3 years ago
5

Solve the following equations: 5–(6+9x)=9–(4x–1)

Mathematics
1 answer:
Advocard [28]3 years ago
8 0

Answer:

x=4/13

Step-by-step explanation:

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Find the slope between (1,-19) and (-2,7)
DanielleElmas [232]
Answer
4



Explanation
(1,19) (-2,7)
7-19=-12
-2-1=-3
The divide -12 and -3 and you get 4
Hope this helps
8 0
3 years ago
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There are 8 triangles in 12 circles what is the simplest ratio triangles to circles
NNADVOKAT [17]

Answer: 8:12,8to12

Step-by-step explanation:

5 0
3 years ago
20 POINTS
denis-greek [22]

Answer:

c. 441ft^2

Step-by-step explanation:

Area is height times length and since it's a square, safe to say that the sides are equal in length. So square root both of the given areas of the 2 square:

\sqrt{841} = 29

\sqrt{400} = 20

Now u have side b and c of the triangle, it's a right triangle so use the Pythagorean theorem a^2 + b^2 = c^2

a^2 + b^2 = c^2

a^2 + 20^2 = 29^2

a^2 + 400 = 841

subtract 4 from both sides

a^2 = 441

square root both sides

\sqrt{a^2} = \sqrt{441}

a = 21

Now the side a of the triangle is also a side of the small square therefore

21^2 = 441

8 0
3 years ago
FIRST TO ANSWER GETS BRALYIST<br> good luck :-)
Ratling [72]

Answer:

My answer is 20ft I'm not really sure but hope this helps

7 0
3 years ago
Memory module consists of 9 chips. The device is designed with redundancy so that it works even if one of its chips is defective
soldier1979 [14.2K]

Answer:

a) P[C]=p^n

b) P[M]=p^{8n}(9-8p^n)

c) n=62

d) n=138

Step-by-step explanation:

Note: "Each chip contains n transistors"

a) A chip needs all n transistor working to function correctly. If p is the probability that a transistor is working ok, then:

P[C]=p^n

b) The memory module works with when even one of the chips is defective. It means it works either if 8 chips or 9 chips are ok. The probability of the chips failing is independent of each other.

We can calculate this as a binomial distribution problem, with n=9 and k≥8:

P[M]=P[C_9]+P[C_8]\\\\P[M]=\binom{9}{9}P[C]^9(1-P[C])^0+\binom{9}{8}P[C]^8(1-P[C])^1\\\\P[M]=P[C]^9+9P[C]^8(1-P[C])\\\\P[M]=p^{9n}+9p^{8n}(1-p^n)\\\\P[M]=p^{8n}(p^{n}+9(1-p^n))\\\\P[M]=p^{8n}(9-8p^n)

c)

P[M]=(0.999)^{8n}(9-8(0.999)^n)=0.9

This equation was solved graphically and the result is that the maximum number of chips to have a reliability of the memory module equal or bigger than 0.9 is 62 transistors per chip. See picture attached.

d) If the memoty module tolerates 2 defective chips:

P[M]=P[C_9]+P[C_8]+P[C_7]\\\\P[M]=\binom{9}{9}P[C]^9(1-P[C])^0+\binom{9}{8}P[C]^8(1-P[C])^1+\binom{9}{7}P[C]^7(1-P[C])^2\\\\P[M]=P[C]^9+9P[C]^8(1-P[C])+36P[C]^7(1-P[C])^2\\\\P[M]=p^{9n}+9p^{8n}(1-p^n)+36p^{7n}(1-p^n)^2

We again calculate numerically and graphically and determine that the maximum number of transistor per chip in this conditions is n=138. See graph attached.

6 0
3 years ago
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