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2 years ago

I can learn new things but I cannot change how good I am at math. A strongly agree B. agree C disagree D. strongly disagree

1 answer:

4 0

Mathematics is a broad subject that anyone who constantly practices by learning from first principle and from example will grow in perfection of the subject as time goes by. Hence, I strongly disagree

During my schools days, I struggled learning mathematics, at the time it was difficult, I began practising and learning from text examples, with time I got a hang of it and my grade and confidence level in the subject increased.

Learn more about Mathematics here:

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It was a children versus grown-ups competition at school. One event required the adult to throw a basketball as far as he could.

Cerrena [4.2K]

D Because If Your Going To Have A Contest Its Ganna Have To Be The Same Objectives For Both Contenders

3 0

3 years ago

Read 2 more answers

1. On each of your equipotential maps, draw some electric field lines with arrow heads indicating the direction of the field. (H

JulijaS [17]

Answer:

The angle between the electric field lines and the equipotential surface is 90 degree.

Explanation:

The equipotential surfaces are the surface on which the electric potential is same. The work done in moving a charge from one point to another on an equipotential surface is always zero.

The electric field lines are always perpendicular to the equipotential surface.

$dV = \overrightarrow{E} . d\overrightarrow{r}\\\\$

For equipotential surface, dV = 0 so

$0 = \overrightarrow{E} . d\overrightarrow{r}\\\\$

The dot product of two non zero vectors is zero, if they are perpendicular to each other.

5 0

2 years ago

I threw a plastic ball in the pool for my dog to fetch. The mass of the ball was 125g. What must the volume be to have a density

Stells [14]

Answer:

250 mL

Explanation:

Density equation:

$Density = \frac{mass}{volume}$

Variables:

D = density

m = mass

V = volume

Solve:

M = 125 g

D = 0.500 g/mL

V = ?

$0.500 g/mL = \frac{125 g}{V}$

V = 250 mL

3 0

3 years ago

Jeff of the Jungle swings on a 7.6-m vine that initially makes an angle of 32 ∘ with the vertical.

shtirl [24]

To solve this problem we will use the trigonometric concepts to find the distance h, which will allow us to find the speed of Jeff and that will finally be the variable that will indicate the total tension, since it is the variable of the centrifugal Force given in the vine at the lowest poing of the swing.

From the image:

$cos (32) = \frac{(7.6-h)}{7.6}$

$h = 1.1548m$

When Jeff reaches his lowest point his potential energy is converted to kinetic energy

$PE = KE$

$mgh = \frac{1}{2} mv^2$

$v = \sqrt{2gh}$

$v = \sqrt{2(9.8)(1.1548)}$

$v= 4.75m/s$

Tension in the string at the lowest point is sum of weight of Jeff and the his centripetal force

$T = W+F_c$

$T = mg + \frac{mv^2}{r}$

$T = (83)(9.8)+\frac{(9.8)( 4.75)^2}{7.6}$

$T = 842.49N$

Therefore the tension in the vine at the lowest point of the swing is 842.49N

3 0

3 years ago

A pitcher claims he can throw a 0.148-kg baseball with as much momentum as a 2.00-g bullet moving with a speed of 1.50 ✕ 103 m/s

Svetlanka [38]

(a) The mass of the bullet is $m_b = 2.00g=0.002 kg$ and its speed is $v_b = 1.5 \cdot 10^3 m/s$ , so its momentum is
$p=m_b v_b = (0.002 kg)(1.5 \cdot 10^3 m/s)=3 kg m/s$

The pitcher claims that he can throw the ball with the same momentum p of the ball. Since the mass of the ball is m=0.148 kg, this means that the velocity of the ball must be:
$v= \frac{p}{m}= \frac{3 kg m/s}{0.148 kg}=20.3 m/s$

(b) The kinetic energy of the bullet is:
$K_b = \frac{1}{2} m_b v_b^2= \frac{1}{2}(0.002 kg)(1.5 \cdot 10^3 m/s)^2=2250 J$

while the kinetic energy of the ball is:
$K= \frac{1}{2}mv^2= \frac{1}{2}(0.148 kg)(20.3 m/s)^2=30.5 J$

So, the bullet has greater kinetic energy than the ball.

4 0

3 years ago

I can learn new things but I cannot change how good I am at math. A strongly agree B. agree C disagree D. strongly disagree​

I can learn new things but I cannot change how good I am at math. A strongly agree B. agree C disagree D. strongly disagree