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3 years ago

Why are electromagnets used in metal scrap yards?

Physics

1 answer:

Artist 52 [7]3 years ago

6 0

Answer:

yes

Explanation:

because they are very very very strong

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Can a object have have zero velocity and nonzero acceleration?

vladimir1956 [14]

Answer:

yes

Explanation:

3 0

3 years ago

What is the arrangement of the forms of electromagnetic radiation according to their wavelengths?

Svetradugi [14.3K]

Gamma rays then x rays then UVA rays then visible light then IR then radio waves (from highest to lowest frequency).

6 0

4 years ago

Consider a double slit experiment in the air. The wavelength of light is 500nm light, the screen is 1m away and two adjacent bri

Bess [88]

Answer: $0.75\ cm$

Explanation:

Given

Wavelength of light $\lambda=500\ nm$

Screen is $D=1\ m$ away

Distance between two adjacent bright fringe is $\Delta y=\dfrac{\lambda D}{d}$

When same experiment done in water, wavelength reduce to $\dfrac{\lambda }{\mu}$

So, the distance between the two adjacent bright fringe is $\Delta y'=\dfrac{\lambda D}{\mu d}$

Keeping other factor same, distance becomes

$\Rightarrow \dfrac{1}{\frac{4}{3}}=\dfrac{3}{4}\quad \text{Refractive index of water is }\dfrac{4}{3}\\\\\Rightarrow 0.75\ cm$

3 0

3 years ago

The equations of kinematics describe the motion of an

Svetradugi [14.3K]

Answer:

The equations of kinematics is applied for the motion with constant acceleration (including zero), but the condition is that the acceleration should be in the direction of the motion (positive or negative).

In circular motion, the acceleration is radial (centripetal), which means that the acceleration is always perpendicular to the motion of the object, therefore the equations of kinematics cannot be applied.

3 0

3 years ago

An asteroid is moving along a straight line. A force acts along the displacement of the asteroid and slows it down. The asteroid

Katena32 [7]

Answer:

666000000000 J

391764.71 N

Explanation:

u = Initial velocity

v = Final velocity

s = Displacement

Change in energy

$\Delta KE=\frac{1}{2}m(v^2-u^2)\\\Rightarrow \Delta KE=\frac{1}{2}3.7\times 10^4(4500^2-7500^2)\\\Rightarrow \Delta KE=-666000000000\ J$

Work done be the force is 666000000000 J

$W=F\times s\\\Rightarrow F=\frac{W}{s}\\\Rightarrow F=\frac{-666000000000}{1.7\times 10^6}\\\Rightarrow F=-391764.71\ N$

The magnitude of force is 391764.71 N

3 0

3 years ago