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tangare [24]
3 years ago
11

An object which has a mass 70 kg is sitting on a cliff 10 m high . Calculate the objects gravitational potential energy given G=

10m/s2
Physics
2 answers:
Lina20 [59]3 years ago
6 0

In physics, potential energy is calculated as ‘mass × acceleration due to gravity × height’

So,

P.E. = 70 kg × 10 m/s² × 10 m

P.E. = 7000 Joules

inysia [295]3 years ago
4 0

Answer: 7000 joules

Explanation: The potential energy is the energy "stored" by the object.

For objects that are lifted in the y-axis, the potential energy can be calculated as:

U = g*h*m

where g is the gravity's acceleration, h is the height and m is the mass of the object.

Here, g = 10m/s^2, m=70kg and h = 10m

U = 10m/s^2*70kg*10m = 7000 (m/s)^2*kg = 7000 joules

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The answer should be C

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Find the kenetic energy of a car of mass 700kg racing with a velocity of 10m/s
fiasKO [112]

Answer:

35000 KJ

Explanation:

The equation for the kinetic energy is given by the formula :

E_{k} = \frac{1}{2} mv^{2}

E_{k} = \frac{1}{2} (700)(10)^{2}

E_{k} = \frac{1}{2} (700)(100)

E_{k} = (350)(100)  OR E_{k} = \frac{1}{2} (70000)

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Units will be kilojoules since the units of mass was kilograms .

Our final answer is 35000 KJ

Hope this helped and have a good day

5 0
2 years ago
Identify two ways in which friction is not useful in science​
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8 0
3 years ago
Two point charges each carrying a charge of + 4.5 E - 6 C are located 4.5 meters away from each other. How strong is the electro
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Answer:

0.009 N, repulsive

Explanation:

The electrostatic force between two electric charges is given by:

F=k\frac{q_1 q_2}{r^2}

where

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r is the separation between the two charges

In this problem, we have

q_1 =q_2 = +4.5\cdot 10^{-6}C are the two charges

r = 4.5 m is their separation

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F=(9\cdot 10^9 Nm^2 C^{-2})\frac{(+4.5\cdot 10^{-6} C)(4.5\cdot 10^{-6} C)}{(4.5 m)^2}=0.009 N

Moreover, the force is repulsive. In fact, the following rules apply:

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