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3 years ago

Describe the energy transformations that occur from the time a skydiver jumps out of a plane until landing on the ground.

2 answers:

6 0

When the Skydiver jump out a plane, his Potential Energy is being converted or transform into Kinetic energy due to gravity. Hope this helps

omeli [17]3 years ago

4 0

Answer:

Before jumping from the plane, the skydiver has potential energy. When the skydiver jumps, the potential energy is transformed into kinetic energy, which increases until the skydiver reaches terminal velocity. Potential energy is then transformed into thermal energy.

Explanation:

Thats the answer

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In diving to a depth of 308 m, an elephant seal also moves 579 m due east of his starting point. What is the magnitude of the se

Kisachek [45]

Answer:

655.82m

Explanation:

By tracing the distances traveled from 308m down in the water and then 579m to the east, a right triangle can be formed and the displacement can be found by the Pythagorean theorem. This is shown in the attached image (the red line is the displacement).

One leg of the triangle will be the 308m

and the second leg of the triangle will be the 579m.

If we call the displacement $x$ , by the pythagorean theorem:

$x=\sqrt{308^2+579^2}$

$x=\sqrt{94,864+335,241}$

$x=\sqrt430,105}$

$x=655.82m$

The displacement is 655.82m

3 0

3 years ago

Physics and chemistry is the study of what?

LenKa [72]

<h3>physical science deals with the study of physics chemistry</h3>

Explanation:

yan lng po Alam ko

8 0

2 years ago

One student suggests using a front-loading washing machine instead of a top-loading washing machine to conserve water. Which of

mariarad [96]

B) It is practical because a top-loading machine uses much more water than a front-loading machine.

Front-loading washing machines are able to better conserve water by automatically maintaining the same water level throughout the wash, while top-loading washing machines generally begin the cycle by filling up the barrel to a certain point.

3 0

3 years ago

Ryan swings a pail of water in a vertical circle 1.0 m in radius at a constant speed. If the water is NOT to spill on him:

nexus9112 [7]

Part 1

If water does not spill at the top point of the circular motion then for the minimum speed condition we can say normal force will be zero at the top position

$F_g = ma$

$mg = m\frac{v^2}{R}$

$g = \frac{v^2}{R}$

$v = \sqrt{Rg}$

given that

R = 1 m

g = 9.8 m/s^2

now from above equation we have

$v = \sqrt{1(9.8)} = 3.13 m/s$

Part b)

for minimum value of angular speed we will have

$\omega = \frac{v}{R}$

$\omega = \frac{3.13}{1}$

$\omega = 3.13 rad/s$

3 0

3 years ago

Two paths lead to the top of a big hill. One is steep and direct, while the other is twice as long but less steep. How much more

umka2103 [35]

Answer:

None.

Explanation:

Gravitational potential energy, depends only of the mass on which the gravity is doing work, and the displacement produced by this force.
As displacement depends only on the final and initial positions (in this case, the height of the hill), if we choose as our zero reference level the bottom of the hill, the change in gravitational potential energy will be as follows:

$\Delta U = U_{f} -U_{0} = m*g*h - 0 = m*g*h$

As we can see, the only value of distance involved is the height of the hill , so it is independent of the distance travelled.

6 0

3 years ago