Answer:
The formula for the calculation of the magnetic field inside a solenoid is
B = μo*n*I
where
μo: vacuum permeability
n: turns per meter
I: current
The magnetic field inside de solenoid is constant. In the case of a small-radius solenoid inside a large-radius solenoid, the magnetic field inside the small-radius solenoid is the magnetic field generated by itself plus the magnetic field generated by the large-radius solenoid. (The radius of the solenoids does not have to be with the instensity of the magnetic field):
BT = Bs + Bl
Bs: magnetic fiel of the small-radius solenoid
Bl: magnetic fiel of the large-radius solenoid
Hence:
BT = 2*μo*n*I
Noise can be measured in decibels.
Answer:
Yes
Explanation:
But I feel also 2 is correct but your answer is right
Answer:
–8.35 m/s²
Explanation:
We'll begin by converting 104 km/h to m/s. This can be obtained as follow:
3.6 Km/h = 1 m/s
Therefore,
104 km/h = 104 km/h × 1 m/s / 3.6 Km/h
104 km/h = 28.89 m/s
Thus, 104 km/h is equivalent to 28.89 m/s.
Finally, we shall determine the deceleration of the car. This can be obtained as follow:
Initial velocity (u) = 28.89 m/s
Final velocity (v) = 0 m/s
Distance (s) = 50 m
Deceleration (a) =?
v² = u² + 2as
0² = 28.89² + (2 × a × 50)
0 = 834.6321 + 100a
Collect like terms
0 – 834.6321 = 100a
–834.6321 = 100a
Divide both side by 100
a = –834.6321 / 100
a = –8.35 m/s²
Thus, the deceleration of the car is –8.35 m/s².
Answer:
107 °F
Explanation:
Given that
The temperature at sea level = 100°F
height ,h= 2000 feet
The average lapse rate = 3.5°F/1000 feet
Given that rise in temperature 3.5°F per 1000 feet.
1000 feet ⇒ 3.5°F
Given that 2000 feet
2000 feet ⇒ 3.5°F x 2 +100°F
2000 feet ⇒ 107 °F
Therefore the temperature will be 107 °F .