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Katyanochek1 [597]
3 years ago
10

I need this fast plz, 50 points

Chemistry
2 answers:
attashe74 [19]3 years ago
6 0

Answer:

It is decreasing the temperature of the reactant mixture.

Explanation:

Just took the test

Margarita [4]3 years ago
4 0

Answer:

increasing the pressure of the reactant mixture

Explanation:

according to the collision theory , the number of collisions that take place per unit volume of the reaction mixture is called collision frequency. The effective collisions are ones which result into the formation of products. It depends on energy factor: For collision to be effective, the colliding molecules must have energy more than a particular value called as threshold energy. increasing the temperature of the reactant mixture, the reactant molecules will gain kinetic energy and thus will increase the number of effective collisions.

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What is the value of the van't Hoff factor for KCl if a 1.00m aqueous solution shows a vapor pressure depression of 0.734 mmHg a
yaroslaw [1]

<u>Answer:</u> The Van't Hoff factor for KCl is 1.74

<u>Explanation:</u>

We are given:

Molality of solution = 1 m

This means that 1 mole of a solute is present in 1 kg of solvent (water) or 1000 grams of water

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}

Given mass of water = 1000 g

Molar mass of water = 18 g/mol

Putting values in above equation, we get:

\text{Moles of water}=\frac{1000g}{18g/mol}=55.56mol

Mole fraction of a substance is given by:

\chi_A=\frac{n_A}{n_A+n_B}

Moles of solute = 1 moles

Total moles = [1 + 55.56] = 56.56 moles

Putting values in above equation, we get:

\chi_{(solute)}=\frac{1}{56.56}=0.0177

The equation used to calculate relative lowering of vapor pressure follows:

\frac{p^o-p_s}{p^o}=i\times \chi_{solute}

where,

\frac{p^o-p_s}{p^o} = relative lowering in vapor pressure = 0.734 mmHg

i = Van't Hoff factor = ?

\chi_{solute} = mole fraction of solute = 0.0177

p^o = vapor pressure of pure water = 23.76 torr

Putting values in above equation, we get:

\frac{0.734}{23.76}=i\times 0.0177\\\\i=1.74

Hence, the Van't Hoff factor for KCl is 1.74

7 0
3 years ago
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