How many moles of CO2 are produced when 3.3 moles of C2H2 react

1 answer:

5 0

To solve this exercise you need to know that to create CO₂ with C₂H₂ is necessary to have oxygen. So, the following balanced equation represents the reaction:
2C₂H₂(g) + 5O₂(g) → 4CO₂(g) + 2H₂O(g)

Notice that 2 moles of C₂H₂ form 4 moles of CO₂, so if 3.3 moles of C₂H₂ react, how many moles of CO2 would be produced?
2 moles of C₂H₂ -------4 moles of CO₂
3.3 moles of C₂H₂--------x moles of CO₂
x=6.6 moles of CO₂ produced.

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A chemistry student needs of isopropenylbenzene for an experiment. He has available of a w/w solution of isopropenylbenzene in a

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Question:

A chemistry student needs of 10 g isopropenylbenzene for an experiment. He has available 120 g of a 42.7% w/w solution of isopropenylbenzene in acetone. Calculate the mass of solution the student should use. If there's not enough solution, press the "No solution" button.

Answer:

The answer to the question is as follows

The mass of solution the student should use is 23.42 g.

Explanation:

To solve the question we note the following

A solution containing 42.7 % w/w of isopropenylbenzene in acetone has 42.7 g of isopropenylbenzene in 100 grams of the solution

Therefore we have 10 g of isopropenylbenzene contained in

100 g * 10 g/ 42.7 g = 23.42 g of solution

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Therefore the quantity to used from the available solution = 23.42 g of the isopropenylbenzene in acetone solution.

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The reaction of pyrrole with bromine forms predominantly __________. View Available Hint(s) The reaction of pyrrole with bromine

xenn [34]

Answer:

a) 2-bromopyrrole

Explanation:

Our options for this questions are:

a) 2-bromopyrrole

b) 2,3-dibromopyrrole

c) N-bromopyrrole

d) 3-bromopyrrole

To understand how the reaction works we have to start with the resonance structures. (Figure 1), on these structures, we will obtain a negative charge on carbon 2 in the pyrrole ring, therefore on this carbon we can generate an attack to an electrophile.

The second step is to check how the mechanism take place. An electrophile is generated by the $Br_2$ and $FeBr_3$ . This electrophile can be attacked by the negative charge on carbon 2 producing the 2-bromopyrrole. (See figure 2).