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Effectus [21]
3 years ago
6

What is the answer for 4(k-6)-(3k+2)= -5

Mathematics
2 answers:
pychu [463]3 years ago
5 0
1 Simplify brackets
4(k-6)-3k-2=-5

2 Expand
4k-24-3k-2=-5

3 Simplify 4k-24-3k-24k−24−3k−2 to k-26
k-26=-5

4 Add 26 to both sides
k=-5+26

5 Simplify -5+26−5+26 to 21
k=21
Dennis_Churaev [7]3 years ago
3 0
We have 4(k-6)-(3k+2)=-5 and the answer is k=21
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  • The function has three distinct real zeros.

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Step-by-step explanation:

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