Answer:
The wavelength the student should use is 700 nm.
Explanation:
Attached below you can find the diagram I found for this question elsewhere.
Because the idea is to minimize the interference of the Co⁺²(aq) species, we should <u>choose a wavelength in which its absorbance is minimum</u>.
At 400 nm Co⁺²(aq) shows no absorbance, however neither does Cu⁺²(aq). While at 700 nm Co⁺²(aq) shows no absorbance and Cu⁺²(aq) does.
Answer:
The hydrolysis in aqueous HCl of compound A can lead to the formation of a carboxylic acid and an alcohol.
Explanation:
The picture shows the structures of compound A, benzoncaine and the possible products of the proposed reaction.
The acidic hydrolysis is the inverse of the esterification reaction. Therefore, the ester group of compund A will react to form the equivalent carboxylic acid and alcohol.
In order to form benzocaine, the hydrolysis happens in with the nitrile group.
