Acetylene has a chemical formula which can be written as:
C2H2
We can see that there are two positive ions, H+. Now what
deprotonation means is that the H+ is removed from acetylene to form acetylene
ion and water. In this case, I believe that the answer would be:
<span>LiOCH3</span>
To relate the quantity of a substance to the amount of heat transferred and heat capacity, temperature, number of moles is given by
q=ncpΔT
where
n is number of moles
cp is molar heat capacity
ΔT=Tfinal−Tinitial is the temperature difference
When dT = Kf * molality * i
= Kf*m*i
and when molality = (no of moles of solute) / Kg of solvent
= 2.5g /250g x 1 mol /85 g x1000g/kg
=0.1176 molal
and Kf for water = - 1.86 and dT = -0.255
by substitution
0.255 = 1.86* 0.1176 * i
∴ i = 1.166
when the degree of dissociation formula is: when n=2 and i = 1.166
a= i-1/n-1 = (1.166-1)/(2-1) = 0.359 by substitution by a and c(molality) in K formula
∴K = Ca^2/(1-a)
= (0.1176 * 0.359)^2 / (1-0.359)
= 2.8x10^-3
