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3 years ago

How does gravity help to demonstrate a cause-and-effect relationship?

Chemistry

2 answers:

Zina [86]3 years ago

7 0

The cause of no gravity means the effect will be we float.

bazaltina [42]3 years ago

6 0

Answer:

Gravity helps show a cause and effect by demostarting how one object will have an effect on another object.

Explanation:

If you bounce a ball, it will fly back up, but it will fall down again because of gravity. The cause is GRAVITY and the effect is the ball FALLINg. Now, because o fgravity, when the ball bounces up again, it will only bounce 1/2 the hieght, having another cause and effect. As gravity pushes down on objects, the more an object is effected by it, the more presure it will have.

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Gasoline is a hydrogen and carbon compound. It is mixed with air in the carburetor of a car. What conditions within the carburet

anzhelika [568]

A poor ratio of Oxygen will cause incomplete combustion and the consequent deposit of carbon.

8 0

3 years ago

A child is swinging back and forth on a swing. Changes in her kinetic and potential energy are happening each moment. At which p

dedylja [7]

Answer:

The maximum potential energy of the child will be maximum at the two end points.

The maximum kinetic energy of the child occurs at the lowest point of the swing.

The potential energy of the child depends on the displacement of the child.

P.E = mgh

The maximum height attained occurs at the two end points of her swing motion.

Thus, the maximum potential energy of the child will be maximum at the two end points.

The kinetic energy of the child depends on the velocity of the child

K.E = ¹/₂mv²

The maximum velocity of the swing occurs at the lowest point of the swing.

Thus, the maximum kinetic energy of the child occurs at the lowest point of the swing.

Hope this helps!

5 0

2 years ago

Read 2 more answers

A 812 g drinking glass is filled with a hot liquid. The liquid transfers 7032 J of energy to the glass. If the temperature of th

JulijaS [17]

Answer:

0.3936 J/gC

Explanation:

using the formula: q=mcΔt

q= 7032J

m=812g

ΔT = 22C

plug in and solve:

7032=(812)(c)(22)

c=7032/(812)(22)

c=0.39 J/gC

7 0

3 years ago

Marat540 [252]

Answer:

The correct option is A) The light moths will be captured by predators more easily than the dark moths, and the population of dark moths will rise.

Explanation:

As we can see, the colour of the trees do not match with the light moths. Instead, the colour of the trees resembles the dark moths. This adaptation will work best for the dark moths to protect it from its predators. The light moths lack this adaptation and can easily be attacked by the predators. Hence, the population of the dark moth will increase as they are better adapted to live in such an environment.

3 0

3 years ago

Solid sodium azide (NaN3) produces solid sodium and nitrogen gas. How many grams of sodium azide are needed to yield a volume of

ch4aika [34]

Answer:

52.008 grams of sodium azide are needed to yield a volume of 26.5 L of nitrogen gas at a temperature of 295 K and a pressure of 1.10 atmospheres.

Explanation:

An ideal gas is characterized by three state variables: absolute pressure (P), volume (V), and absolute temperature (T). The relationship between them constitutes the ideal gas law, an equation that relates the three variables if the amount of substance, number of moles n, remains constant and where R is the molar constant of the gases:

P*V = n*R*T

In this case, the balanced reaction is:

2 NaN₃ → 2 Na + 3 N₂

You know the following about N₂:

P= 1.10 atm
V= 26.5 L
n=?

$R=0.082057 \frac{atm*L}{mol*K}$

T= 295 K

Replacing in the equation for ideal gas:

1.10 atm* 26.5 L= n* $0.082057 \frac{atm*L}{mol*K}$ *295 K

Solving:

$n=\frac{1.10 atm*26.5 L}{0.082057 \frac{atm*L}{mol*K} *295K}$

n= 1.2 moles

Now, the following rule of three can be applied: if 3 moles of N₂ are produced by stoichiometry of the reaction from 2 moles of NaN₃, 1.2 moles of N₂ are produced from how many moles of NaN₃?

$moles of NaN_{3}=\frac{1.2 molesofN_{2} *2 molesofNaN_{3} }{3 molesofN_{2} }$

moles of NaN₃= 0.8

Since the molar mass of sodium azide is 65.01 g / mol, then one last rule of three applies: if 1 mol has 65.01 grams of NaN₃, 0.8 mol how much mass does it have?

$mass of NaN_{3} =\frac{0.8 mol*65.01 grams}{1 mol}$

mass of NaN₃=52.008 grams

52.008 grams of sodium azide are needed to yield a volume of 26.5 L of nitrogen gas at a temperature of 295 K and a pressure of 1.10 atmospheres.

6 0

3 years ago

Read 2 more answers