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Korolek [52]
3 years ago
7

How does gravity help to demonstrate a cause-and-effect relationship?

Chemistry
2 answers:
Zina [86]3 years ago
7 0
The cause of no gravity means the effect will be we float.
bazaltina [42]3 years ago
6 0

Answer:

Gravity helps show a cause and effect by demostarting how one object will have an effect on another object.

Explanation:

If you bounce a ball, it will fly back up, but it will fall down again because of gravity. The cause is GRAVITY and the effect is the ball FALLINg. Now, because o fgravity, when the ball bounces up again, it will only bounce 1/2 the hieght, having another cause and effect. As gravity pushes down on objects, the more an object is effected by it, the more presure it will have.

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1. At what temperature dose water freeze
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Answer:

1. water will freeze at a temperature below 32 degrees fahrenheit 0 degree celsius.

2. Ice will melt at a temperature above 32 degrees fahrenheit 0 degrees celsius.

3. water boils at 212 degrees fahrenheit or 100 degrees celsius.

8 0
2 years ago
When a reaction takes place in a SEALED FLASK,<br> the TOTAL MASS of the system...
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It should remain constant because of the law of conservation of mass and because the flask is sealed no mass will escape
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3 years ago
What causes some aqueous solutions to have a low PH?
noname [10]
<span> Low pH means the solution is acidic; if the solution is acidic, that means that there are hydronium ions in solution (H3O+). For example, hydrochloric acid dissolves into H+ ions and Cl- ions, and the H+ ions rreact with water like this:
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5 0
3 years ago
What volume of lead (of density 11.3 g/cm3 ) has the same mass as 395 cm3 of a piece of redwood (of density 0.38 g/cm3 )? Answer
Zepler [3.9K]
d_{1}=\frac{m}{V_{1}}\\\\&#10;V_{1}=395cm^{3}\\&#10;d_{1}=0,38\frac{g}{cm^{3}} \ \ \ \ \Rightarrow \ \ \ \ m=395cm^{3}*0,38\frac{g}{cm^{3}}=150,1g\\\\\\&#10;d_{2}=\frac{m}{V_{2}}\\\\&#10;m=150,1g\\&#10;d_{2}=11,3\frac{g}{cm^{3}} \ \ \ \ \Rightarrow \ \ \ \ V_{2}=\frac{150,1g}{11,3\frac{g}{cm^{3}}}\approx13,28cm^{3}
8 0
3 years ago
A 200. gram sample of a salt solution contains 0.050 grams of NaCl. What is the concentration of the
wariber [46]

Answer:

2.5 × 10² ppm

Explanation:

Step 1: Given data

  • Mass of NaCl: 0.050 g
  • Mass of the sample: 200. g

Step 2: Convert 0.050 g to μg

We will use the conversion factor 1 g = 10⁶ μg.

0.050 g × 10⁶ μg/1 g = 5.0 × 10⁴ μg

Step 3: Calculate the concentration of NaCl in ppm

The concentration of NaCl in ppm is equal to the micrograms of NaCl per gram of the sample.

5.0 × 10⁴ μg NaCl/200. g = 2.5 × 10² ppm

3 0
3 years ago
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