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3 years ago

X-y=1 this is on my homerork assignment and i want to know how to grap it

1 answer:

8 0

To more easily graph this, convert it to slope-intercept form (y = mx + b, where m is the slope and b is the y-intercept):

x - y = 1
-y = -x + 1
y = x - 1

The slope is 1 and the y-intercept is -1. To graph this, plot the point (0, -1) and count 1 unit down and 1 unit to the right. Do this once more, connect the points, and you have your line.

Hope this helps.

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3 years ago

Find the length of the diagonal of an 8cmx 6cmx 10cm rectangular prism. Round to the nearest tenth. (HELP PLEASE!!)

Hatshy [7]

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14.1 cm

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4 years ago

The area of a photograph is 35 square inches. Its length is two inches longer than its width. Find the length and width of

devlian [24]

Answer:

length is 7 inches and the width is 5 inches

Step-by-step explanation:

Hello, I think I can help you with this

the area of a rectangle is given by:

$(equation1)Area=length * width\\$

Step 1

According to the question data,the length is two inches longer than its width.which means that you can take the width and add 2 inches to obtain the length, in mathematical terms

(equation 2)Width + 2 inches = length

Step 2

Now, put equation 2 into equation 1

$Area=length * width\\Area=(width + 2 )*width\\Area=width^{2}+2widht\\Let\ width=w$

Step 3

replace and solve for w

Let

A=35

$A=35\\Area=w^{2} +2w\\35=w^{2} +2w\\w^{2} +2w-35=0\\use\ quadratic\ formula\ to\ solve\\if\\ax^{2} +bx+c=0\\x=\frac{-b +- \sqrt[2]{b^{2}4ac } }{2a}\\ +- means\ there\ are\ 2\ solutions, we\ will\ take\ the\ positive\ one, because\ it\ is\ a\ distance.\\Now, replacing\\a=1,b=2,c=35\\\\w=\frac{-2 + \sqrt[2]{2^{2}-4*1*-35 } }{2*1}\\w=\frac{-2 + \sqrt[2]{4+140} }{2}\\w=\frac{-2+\sqrt{144} }{2} \\w=\frac{-2+12}{2}\\w=\frac{10}{2}\\w=5$

so, the width is 5 inches,

replacing this value in equation 2

Width + 2 inches = length

5 in +2 in =length

7 in = length

so , the length is 7 inches

Have a good day.

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3 years ago