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astra-53 [7]
3 years ago
12

Some atoms are chemically stable and will not bond with atoms of other

Chemistry
2 answers:
tigry1 [53]3 years ago
7 0

Answer:

The stability of atoms depends on whether or not their outer-most shell is filled with electrons. If the outer shell is filled, the atom is stable. Atoms with unfilled outer shells are unstable, and will usually form chemical bonds with other atoms to achieve stability.

Explanation:

riadik2000 [5.3K]3 years ago
4 0

Answer:

The stability of atoms depends on whether or not their outer-most shell is filled with electrons. If the outer shell is filled, the atom is stable. Atoms with unfilled outer shells are unstable, and will usually form chemical bonds with other atoms to achieve stability.

Explanation:

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16 I think hopefully
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How could you increase the power of a wave in a spring
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Methane, the principal component of natural gas, is used for heating and cooking. The combustion process is CH4(g) + 2 O2(g) → C
antoniya [11.8K]

Answer:

392.97 litres

Explanation:

From the equation of reaction, we can see that 1 mole of methane yielded 1 mole of carbon iv oxide. Hence, 15.9 moles of methane will yield 15.9 moles of carbon iv oxide.

At s.t.p one mole of a gas occupies a volume of 22.4L ,hence 15.9 moles of a gas will occupy a volume of 22.4 × 15.9 which equals

356.16L.

Now, we can use the general gas equation to get the volume produced at the values given.

We have the following values;

V1 = 356.16L P1= 1 atm ( standard pressure) T1 = 273K ( standard temperature) V2 = ? T2 = 23.7 + 273 = 296.7K P2 = 0.985 atm

The general form of the general gas equation is given as :

(P1V1)T1 = (P2V2)/T2

After substituting the values , we get V2 to be 392.97Litres

8 0
2 years ago
What is the enthalpy change for this reaction?
Mrrafil [7]

Answer:

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5 0
2 years ago
14.Sorbitol is used in sugar free gums as a sweetener. After analysis, a sample of
evablogger [386]
<h3>Answer:</h3>

C6H12O6

Explanation:

To find empirical formular you write out the element

Carbon Hydrogen Oxygen

3.96 769 5.28

then u althrough divide by their atomic numbers

3.96÷ 12 769÷1 5.28÷16

=0.33 =769 =0.33

also divide althrough by the lowest number

the lowest number is 0.33 so we use it to divide

0.33÷0.33. 769÷0.33. 0.33÷0.33

= 1 = 2 = 1

empirical formular= CH2O

To find the Molecular formular

Molecular number = molar mass

(CH2O)n = 182

(12+1×2+16)n = 182

30n = 182

n = 6

therefore the Molecular formular is C6H12O6

3 0
1 year ago
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