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Tema [17]
3 years ago
12

How many joules are released when one atom of americium 241, the isotope used in ionization-type smoke detectors, undergoes apha

emission?
Chemistry
1 answer:
klemol [59]3 years ago
4 0

When Americium (Am-241) undergoes alpha decay(He-4) it forms neptunium (Np-237) based on the following pathway:

²⁴¹Am₉₅ → ²³⁷Np₉₃ + ⁴He₂

The energy released in given as:

ΔE = Δmc²

where Δm = mass of products - mass of reactants

                 = [m(Np-237) + m(He-4)] - [m(Am-241)]

                 = 237.0482+4.0015-241.0568 = -0.0073 g/mol = -7.3 * 10⁻⁶ kg/mol

ΔE = -7.3*10⁻⁶ kg/mol * (3*10⁸ m/s)² = -5.84*10¹¹ J/mol



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Explanation:

  • We need to find the amount of carbon dioxide gas in 1.505\times 10^{23} molecules of the gas.
  • We know that, 1 mole weighs 44 gram of carbon dioxide which contains 6.022\times 10^{23} number of molecules. It means that, 6.022\times 10^{23} number of molecules present in 44 grams of carbon dioxide molecule. So,1.505\times 10^{23}  number of molecules present in :

=\dfrac{1.0505\times 10^{23}}{6.022\times 10^{23}}\times 44\\\\=7.675\ \text{grams}

  • Hence, 7.675 grams of carbon dioxide is present in 1.505\times 10^{23} molecules of the gas.
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Answer:

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Explanation:

<em>The correct option would be that the average kinetic energy of the gas particles is greater in container B because it has a higher temperature.</em>

<u>According to the kinetic theory of matter, the temperate of a substance is a measure of the average kinetic energy of the molecules of substance. In other words, the higher the temperature of a substance, the higher the average kinetic energy of the molecules of the substance.</u>

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