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Alik [6]
3 years ago
14

A beaker contains 0.125 L of a 3.00 M solution. If the volume goes up to 0.325 L, what is the new molarity?

Chemistry
1 answer:
igor_vitrenko [27]3 years ago
8 0

Answer:

1.15 M

Explanation:

Step 1: Given data

  • Initial volume (V₁): 0.125 L
  • Initial concentration (C₁): 3.00 M
  • Final volume (V₂): 0.325 L
  • Final concentration (C₂): ?

Step 2: Calculate the final concentration of the solution

We want to prepare a dilute solution from a concentrated one by adding water. We can calculate the concentration of the dilute solution using the dilution rule.

C₁ × V₁ = C₂ × V₂

C₂ = C₁ × V₁/V₂

C₂ = 3.00 M × 0.125 L/0.325 L = 1.15 M

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What do geologists call the underground molten mixture of rock-forming substances, gases, and water that is found in the mantle?
Likurg_2 [28]

Answer:

B.) Magma

Explanation:

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6 0
3 years ago
PLS I NEED HELP give me examples of an atom
Ugo [173]

Answer:

Neon (Ne)

Hydrogen (H)

Argon (Ar)

Iron (Fe)

Calcium (Ca)

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Explanation:

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4 0
3 years ago
The decomposition of potassium chlorate into kcl &amp; o2 is used as a source of oxygen in the laboratory. How many moles of pot
fredd [130]

Answer:

10moles of kcl

Explanation:

2 K C l O3 →  2 K C l  +  3 O 2

Notice that you have a  2 : 3  mole ratio between potassium chlorate and oxygen gas, which means that, regardless of how many moles of the former react, you'll always produce 2/3 times more moles of the latter.

15 mol of O2 * ((2mol of KCLO3)/(3mol of O2))= 15*2/3=10 Mol

5 0
4 years ago
What is the name of the isotope produced when Californium-251 emits an alpha particle?
Charra [1.4K]
<h3>Answer:</h3>

                 Curium-247 <em>i.e.</em> ²⁴⁷₉₆Cm

<h3>Explanation:</h3>

Alpha decay is given by following general equation,

                              ᵃₓA    →    ⁴₂He  +  ᵃ⁻⁴ₓ₋₂B

Where;

           A  =  Parent Isotope

           B  =  Daughter Isotope

           ᵃ  =  Mass Number

           ₓ  =  Atomic Number

Californium-251 is the parent isotope in our case and it has 98 protons (atomic number) and is given as,

                                                 ²⁵¹₉₈Cf

The alpha decay reaction of Californium-251 will be as,

                               ²⁵¹₉₈Cf     →     ⁴₂He  +  ²⁴⁷₉₆B

The symbol for B with atomic number 96 was found to be the atom of Curium (Cm) by inspecting periodic table. Hence, the final equation is as follow,

                               ²⁵¹₉₈Cf     →     ⁴₂He  +  ²⁴⁷₉₆Cm

3 0
3 years ago
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