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2 years ago

A beaker contains 0.125 L of a 3.00 M solution. If the volume goes up to 0.325 L, what is the new molarity?

Chemistry

1 answer:

igor_vitrenko [27]2 years ago

8 0

Answer:

1.15 M

Explanation:

Step 1: Given data

Initial volume (V₁): 0.125 L

Initial concentration (C₁): 3.00 M

Final volume (V₂): 0.325 L

Final concentration (C₂): ?

Step 2: Calculate the final concentration of the solution

We want to prepare a dilute solution from a concentrated one by adding water. We can calculate the concentration of the dilute solution using the dilution rule.

C₁ × V₁ = C₂ × V₂

C₂ = C₁ × V₁/V₂

C₂ = 3.00 M × 0.125 L/0.325 L = 1.15 M

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Answer:

To supply the required ions it is necessary to inject 5,6mL of 6g/30mL solution and 131,1 mL of 0,9% solution.

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To supply the potassium ion it is necessary to inject:

1,125g of KCl× $\frac{30mL}{6g}$ = 5,6mL of 6g/30mL solution

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3 years ago

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Answer:

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3 years ago

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