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Alina [70]
3 years ago
10

1. How much do you like pepsi between 0-10. 2.how much do you like diet sodas between 0-10. Please answerr dont delete its my pr

oject...
Chemistry
1 answer:
alexdok [17]3 years ago
6 0

I'm not sure if this is a personal question or not but I am going to take it as it is.

Personally, I like Coca-cola than I do Pepsi I have to say for a pepsi it'd be 5/10.

I don't really enjoy drinking diet soda's because the ingredients so I have to say 3/10.

This is my personal opinion. You can easily answer this question if you drink soda and if you don't just add that into your project.

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Margarita [4]
It seems that you have missed the necessary options for us to answer this question, but anyway, here is the answer. The type of medium that a compression wave can be transmitted through is liquids only. <span>When a wave moves faster than the local speed of sound in a fluid, it is a shock wave. Hope this answer helps. </span>
3 0
3 years ago
Read 2 more answers
Balance this chemical equation.
Vadim26 [7]

Answer:

Explanation:

Reaction Given

    NaHCO₃ (s) + HC₂H₃O₂ (aq) -------> CO₂ (g) + H₂O (l) + NaC₂H₃O₂ (aq)

Balance Equation = ?

Solution:

Balance Chemical Equation:

A balanced chemical equation is that in which the number of the reactant atoms equal to the number of the product atom.

For example if the carbon at the reactant side is 3, the number of carbon must be 3 on the product side.

Check the chemical equation and count the number of atoms at the reactant side and product side.

If the number of atoms of the reactants equal to the number of atoms of products then the reaction is balanced but if not equal then reaction is not balanced

Balancing is an trial and error process to get a balance reaction.

First we count the number of atoms of reactant and product

Number of atoms of Reactant:

Na = 1

O = 5

H = 5

C = 3

Number of atoms of Product:

Na = 1

O = 5

H = 5

C = 3

So this a balance equation as the atoms of the reactant atom equal to the number of the product atoms.

Na atom is 1 on both reactant and product side

Oxygen atoms are 5 on reactant and 5 on product side

hydrogen atoms are 5 on reactant and 5 on product side

Carbon atoms are 3 on reactant and 3 on product side

So all the compounds in the reaction have 1 as its coefficient in the blanks

<u />

<u>1   </u>NaHCO₃ (s) +  <u>1  </u>HC₂H₃O₂ (aq) -----> <u>1  </u>CO₂ (g) + <u>1  </u>H₂O (l) + <u>1  Na</u>C₂H₃O₂ (aq)

7 0
3 years ago
The bond that join the 3'-hydroxyl group of the deoxypentose of one nucleotide to the 5'-hydroxyl group of the deoxypentose of a
lara [203]

Answer:

phosphodiester bond

Explanation:

<em>Phosphodiester linkage/bond is found in deoxyribonucleic and ribonucleic acids. It is formed from a reaction involving the elimination of water from a reaction involving the hydroxyl groups of two different 5-carbon (pentose) sugars and a phosphate group.</em>

The elimination of water, also known as condensation reaction occur twice, resulting in the formation of two ester bonds which then bind the phosphate group to the pentose sugars to become a phosphodiester bond.

The bond links the 3'-hydroxyl group of one of the pentose sugars and the 5'-hydroxyl group of the other pentose sugar in the nucleotides that make up nucleic acids.

8 0
3 years ago
A solution is made containing 14.6g of CH3OH in 185g H2O.1. Calculate the mole fraction of CH3OH.2. Calculate the mass percent o
Andre45 [30]

Answer:

* x_{CH_3OH}=0.0425

* \%m/m_{CH_3OH}=7.31\%

* m=2.46m

Explanation:

Hello,

In this case, for the mole fraction of methanol we use the formula:

x_{CH_3OH}=\frac{n_{CH_3OH}}{n_{CH_3OH}+n_{water}}

Thus, we compute the moles of both water (molar mass 18 g/mol) and methanol (molar mass 32 g/mol):

n_{CH_3OH}}=14.6g*\frac{1mol}{32g}=0.456molCH_3OH \\\\n_{water}}=185g*\frac{1mol}{18g}=10.3molH_2O

Hence, mole fraction is:

x_{CH_3OH}=\frac{0.456mol}{0.456mol+10.3mol}\\\\x_{CH_3OH}=0.0425

Next, mass percent is:

\%m/m_{CH_3OH}=\frac{m_{CH_3OH}}{m_{CH_3OH}+m_{water}}*100\%\\\\\%m/m_{CH_3OH}=\frac{14.6g}{14.6g+185g}*100\%\\\\\%m/m_{CH_3OH}=7.31\%

And the molality, considering the mass of water in kg (0.185 kg):

m=\frac{n_{CH_3OH}}{m_{water}} =\frac{0.456mol}{0.185kg}\\ \\m=2.46m

Regards.

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Answer:

c. they carry energy is the answer

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