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Alina [70]
3 years ago
10

1. How much do you like pepsi between 0-10. 2.how much do you like diet sodas between 0-10. Please answerr dont delete its my pr

oject...
Chemistry
1 answer:
alexdok [17]3 years ago
6 0

I'm not sure if this is a personal question or not but I am going to take it as it is.

Personally, I like Coca-cola than I do Pepsi I have to say for a pepsi it'd be 5/10.

I don't really enjoy drinking diet soda's because the ingredients so I have to say 3/10.

This is my personal opinion. You can easily answer this question if you drink soda and if you don't just add that into your project.

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3 years ago
Define An Atom.<br>Ty!!!​
astra-53 [7]

Answer:

the basic unit of a chemical element.

Explanation:

5 0
3 years ago
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How many grams of a 22.9% sugar solution contain 68.5 g of sugar?
777dan777 [17]

    The grams  of 22.9 %   sugar  solution that contain 68.5  g  of   sugar  is 299.13 g  of  solution  

   <u><em>calculation</em></u>

 22.9%  means that  there are  22.9 g  of  sugar  in 100 g of solution.

   what about   68.5 g  of sugar

- <em>by cross    multiplication</em>

=[(68.5 g  sugar x 100  g  solution) /22.9  g sugar] =299.13 g  of solution

Nb; <em>g sugar cancel  each other</em>

5 0
3 years ago
write equations to show the chemical processes which occur when the first ionization and the second ionization energies of lithi
diamong [38]

Answer:

First ionization of lithium:

\text{Li}\;(g)\to \text{Li}^{+} \; (g) + \text{e}^{-}.

Second ionization of lithium:

\text{Li}^{+}\;(g) \to\text{Li}^{2+} \;(g) + \text{e}^{-}.

Explanation:

The ionization energy of an element is the energy required to remove the outermost electron from an atom or ion of the element in gaseous state. (Refer to your textbook for a more precise definition.) Some features of the equation:

  • Start with a gaseous atom (for the first ionization energy only) or a gaseous ion. Write the gaseous state symbol (g) next to any atom or ion in the equation.
  • The product shall contain one gaseous ion and one electron. The charge on the ion shall be the same as the order of the ionization energy. For the second ionization energy, the ion shall carry a charge of +2.
  • Charge shall balance on the two sides of the equation.

First Ionization Energy of Li:

  • The products shall contain a gaseous ion with charge +1 \text{Li}^{+}\;(g) as well as an electron \text{e}^{-}.
  • Charge shall balance on the two sides. There's no net charge on the product side. Neither shall there be a charge on the reactant side. The only reactant shall be a lithium atom which is both gaseous and neutral: \text{Li}\;(g).
  • Hence the equation: \text{Li}\;(g) \to \text{Li}^{+}\;(g) + \text{e}^{-}.

Second Ionization Energy of Li:

  • The product shall contain a gaseous ion with charge +2: \text{Li}^{2+}\;(g) as well as an electron \text{e}^{-}.
  • Charge shall balance on the two sides. What's the net charge on the product side? That shall also be the charge on the reactant side. What will be the reactant?
  • The equation for this process is \text{Li}^{+} \; (g) \to \text{Li}^{2+}\;(g) + \text{e}^{-}.
5 0
3 years ago
If the change in entropy of the surroundings for a process at 451 k and constant pressure is -326 j/k, what is the heat flow abs
Arisa [49]

If the change in entropy of the surroundings for a process at 451 k and constant pressure is -326 j/k, then heat flow absorbed (in kj) by the system is -147.026kJ.

<h3>What is entropy? </h3>

The entropy of particle is defined as how random it move. It shows the randomness of the system or may be disorders of the system. It is used to measure the unavailable energy for performing useful work.

Unit of entropy = J/K

<h3>Formula:</h3>

∆s = ∆Q/T

where,

∆s = change in entropy of the surrounding = -326J/K

∆Q = heat absorbed from surrounding

T = Temperature = 451K

∆Q = ∆s × T

∆Q = -326 × 451

∆Q = 147,026 J

∆Q = 147.026 kJ

Thus we find that the heat absorbed by the system is 147.026 kJ.

learn more about entropy:

brainly.com/question/14131507

#SPJ1

8 0
2 years ago
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