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IRINA_888 [86]
3 years ago
12

A rectangular deck has an area of 320ft^2. the length of the deck is 4 feet longer than the width. find the dimensions of the de

ck. solve by completing the square.
Mathematics
1 answer:
Digiron [165]3 years ago
7 0
A = L * W
A = 320
L = W + 4

320 = W(W + 4)
320 = W^2 + 4W
W^2 + 4W = 320
W^2 + 4W + 4 = 320 + 4
(W + 2)^2 = 324
W + 2 = (+-) sqrt 324
W = -2 (+-) 18

W = -2 + 18 = 16 ft <== this is the width
W = -2 - 18 = -20....not this one because it is negative

L = W + 4
L = 16 + 4
L = 20 ft <=== this is the length

in summary...the width is 16 ft and the length is 20 ft 

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Step-by-step explanation:

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first, from the information given to us,

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from our solution, t = 14, v = 13

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14 + 7 + w

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