Answer:
41.7feet
Step-by-step explanation:
From the question we are given the following
angle of depression = 50°
Distance of the pole from the base of the feet = 35feet (Adjacent)
Required
height of the school (opposite)
Using the SOH CAH TOA identity
Tan theta = opp/adj
Tan 50 = H/35
H = 35tan 50
H = 35(1.1918)
H = 41.7feet
Hence the height of the school is 41.7feet
Answer:
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Step-by-step explanation:
Answer:
72
Step-by-step explanation:
<1 and <2 are not equal to each other
Let the angle directly above angle 2 (on the right side of the line) be angle 3
<1 and <3 are corresponding angle, which means they are equal
<2 and <3 are supplementary angles since the form a line
<2 + <3 = 180
We know <1 = <3
<1 + <3 = 180
We are given <1 = 2x+12 and <2 = 3x+18
2x+12 + 3x+18 = 180
Combine like terms
5x+30 = 180
Subtract 30 from each side
5x+30-30 = 180-30
5x= 150
Divide each side by 5
5x/5 = 150/5
x=30
<1 = 2x+12
Substitute 30 in for x to find angle 1
= 2*30 +12
=60+12
= 72
Answer: there are no solutions
Step by step: Step 1: Simplify both sides of the equation.
3
(
x
−
1
)
=
5
x
+
3
−
2
x
(
3
)
(
x
)
+
(
3
)
(
−
1
)
=
5
x
+
3
+
−
2
x
(Distribute)
3
x
+
−
3
=
5
x
+
3
+
−
2
x
3
x
−
3
=
(
5
x
+
−
2
x
)
+
(
3
)
(Combine Like Terms)
3
x
−
3
=
3
x
+
3
3
x
−
3
=
3
x
+
3
Step 2: Subtract 3x from both sides.
3
x
−
3
−
3
x
=
3
x
+
3
−
3
x
−
3
=
3
Step 3: Add 3 to both sides.
−
3
+
3
=
3
+
3
0
=
6
Cancel something
we cancel x's
multiply 1st equation by 5 and 2nd by 7 and add them
-35x-30y=-5
<u>35x-28y=7 +</u>
0x-58y=2
-58y=2
divide both sides by -58
y=-1/29
sub back
5x-4(-1/29)=1
5x+4/29=1
minus 4/29 from both sides
note, 1=29/29
5x=25/29
divide bot sides by 5 (or times 1/5)
x=5/29
(5/29,-1/29)