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two years ago, you purchased 220 shares of ibm stock for $124 a share. today, you sold your ibm stock for $142 a share. for this problem, ignore commissions that would be charged to buy and sell your ibm shares and dividends you might have received as a shareholder.
The range for daily sales for the week, $89,000, $75,000, $98,000, $66,000, and $99,000, is ________. a. $33,000. b. $85,400. c.
Ann [662]
Answer:
$33,000
Explanation:
The daily sales for a particular week is given as follows: $89,000, $75,000, $98,000, $66,000, $99,000
Range can be defined as the difference between the highest value and the lowest value within a particular set of number
From the question above;
The highest value is $99,000
The lowest value is $66,000
Therefore, the range for the daily sales for the week can be calculated as follows
Range= Highest value-Lowest value
= $99,000-$66,000
= $33,000
Hence the range is $33,000
Answer:
The opportunity cost for a year will be $240,000.
Explanation:
The opportunity cost of any decision is the second-best alternative that is given up or sacrificed.
Here, the manager has a farm of 100 acres of land.
If he sells it to a developer for $40,000 per acre, he will get $4,000,000 for the whole land.
He can invest this amount and get an interest of 6% per year.
The opportunity cost of keeping the farm to the manager himself will be
= 6% of $4,000,000
=
= $240,000
Answer:
At 6% $3,529.412 will be invested
At 11% $6,470.588 will be invested
Explanation:
Let x be the investment for 6% stock
And (10,000-x) is the investment it 11% stock
Let I be interest earned on both investments.
Using the formula
Principal(p)= Interest(I)*Rate(r)*Time(t)
p/RT= I
So considering both investments
x/(6%*1)= (10,000-x)/(11%*1)
x/0.06= (10,000-x)/0.11
Cross-multiply
0.11x= 0.06(10,000-x)
0.11x= 600- 0.06x
Rearranging
0.11x+ 0.06x= 600
0.17x= 600
x= 600/0.17= 3,529.412 amount invested at 6%
Amount invested at 11%= 10,000-3,529.412
= 6,470.588
It is c.equity capital I know it is the answer