Answer: A. Cilla Is Correct.
Answer:
The nitrogens are both sp3 hybridized. Their bonds are formed by sp overlaps. The carbon and oxygen are sp2 hybridized. The double bond with oxygen is produced by a sp2 overlap to form the sigma component and a probital overlap to form the pi component. The bonds with hydrogen are formed by sp2 overlaps.
Explanation:
Answer:
The answer is 18.12KJ is required to vaporise 48.7 g of dichloromethane at its boiling point
Explanation:
To solve the above question we have the given variable as follows
ΔHvap = heat of vaporisation of dichloromethane per mole = 31.6KJ/mole
However since the heat of vaporisation is the heat to vaporise one mole of dichloromethane, then, for 48.7 grams of dichloromethane, we have.
The number of moles of dichloromethane present = 48.7/84.93 = 0.573 moles
Therefore, the amount of heat required to vaporise 48.7 grams of dichloromethane at its boiling point is 31.6KJ/mole×0.573moles =18.12KJ
Combustion means the burning of something. So in the given question, you could say, “In this question, combustion means the burning of methane”.
Given :
Energy , E = 330 J .
Initial temperature , 
.
Final temperature , 
.
Mass of benzene , m = 24.6 g .
To Find :
The molar hear capacity of benzene at constant pressure .
Solution :
Molecular mass of benzene , M = 78 g/mol .
Number of moles of benzene :
Energy required is given by :
Hence , this is the required solution .
