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2 years ago

What is the average velocity of atoms in 1.00 mol of argon (a monatomic gas) at 275 K? For m, use 0.0399 kg. (1 point)

Chemistry

1 answer:

valentinak56 [21]2 years ago

6 0

What is the average velocity of atoms in 1.00 mol of argon (a monatomic gas) at 275 k for m, use 0.0399kg

Answer: The average velocity of the atoms 847.33 m/s.

Explanation:

Moles of the neon = 1.00

Temperature of the gas : 288 K

Mass of the gas = 0.01000

R = 8.31 J/mol K

The average velocity of the atoms 847.33 m/s.

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A balloon contains 3.20 L of helium. The pressure is reduced to 59.0 kPa, and the

pshichka [43]

Answer:

101.4pKa

Explanation:

Given parameters:

Initial Volume of helium = 3.20L

Final pressure of helium = 59kPa

Final volume on helium gas = 5.5L

Unknown:

Initial pressure exerted on the balloon = ?

Solution;

To solve this pressure - volume problem, we simply apply the Boyle's law.

It states that "the volume of a fixed mass gas varies inversely as the pressure changes if the temperature is constant".

Mathematically;

P1 V1 = P2 V2

Now, insert parameters and solve;

P1 x 3.2 = 59 x 5.5

P1 = 101.4pKa

4 0

2 years ago

For the reaction below, Kp = 1.16 at 800.°C. CaCO3(s) equilibrium reaction arrow CaO(s) + CO2(g) If a 25.0-g sample of CaCO3 is

goblinko [34]

Answer:

76.0%

Explanation:

Let's consider the following reaction.

CaCO₃(s) ⇄ CaO(s) + CO₂(g)

At equilibrium, the equilibrium constant Kp is:

Kp = 1.16 = pCO₂ ⇒ pCO₂ = 1.16 atm

We can calculate the moles of CO₂ at equilibrium using the ideal gas equation.

$P.V=n.R.T\\n=\frac{P.V}{R.T} =\frac{1.16atm\times 14.4 L}{(0.08206atm.L/mol.K)\times 1073K} =0.190mol$

From the balanced equation, we know that 1 mole of CO₂ is produced by 1 mole of CaCO₃. Taking into account that the molar mass of CaCO₃ is 100.09 g/mol, the mass of CaCO₃ that reacted is:

$0.190molCO_{2}.\frac{1molCaCO_{3}}{1molCO_{2}} .\frac{100.09gCaCO_{3}}{1molCaCO_{3}} =19.0gCaCO_{3}$

The percentage by mass of the CaCO₃ that reacted to reach equilibrium is:

$\frac{19.0g}{25.0g} \times 100\%=76.0\%$

5 0

2 years ago

A liquid sample, with a density of .0915 g/mL has a mass of 17.7 grams.

Arlecino [84]

The relation between density, mass and volume is

$Density = \frac{Mass}{Volume}$

1) to calculate = volume

given:

Density = 0.0915 g/ mL

mass = 17.7 grams

formula used:

$Density = \frac{Mass}{Volume}$

Thus

Volume $Volume = \frac{Mass}{Density} = \frac{17.7 g}{0.915 \frac{g}{mL} } = 193.44 mL$

Answer: 193.44 mL

2) the mass of sample will be

$mass = density X volume = 0.0915\frac{g}{mL} X 76.5 mL = 6.99 = 7 g$

Answer: 7 g

5 0

2 years ago

Which atom has the weakest attraction for electrons in a chemical bond? A) a boron atom B) a calcium atom C) a fluorine atom D)

Black_prince [1.1K]

<span> The answer is
B) a calcium atom</span>

3 0

3 years ago

Differentiate between a precipitate and an aqueous solution

antiseptic1488 [7]

Answer:

A precipate is a solid while an aqueous solution is liquid.

Explanation:

A precipitate is a solid which separates after a chemical reaction occurs. It is the solid product of the reaction.

An aqueous solution is formed when a substance is dissolved in water.

6 0

3 years ago